let F be Field; for p being non zero Polynomial of F st ex a being Element of F st multiplicity (p,a) > 1 holds
card (Roots p) < card (BRoots p)
let p be non zero Polynomial of F; ( ex a being Element of F st multiplicity (p,a) > 1 implies card (Roots p) < card (BRoots p) )
H:
card (Roots p) <= card (BRoots p)
by RING_5:65;
assume
ex a being Element of F st multiplicity (p,a) > 1
; card (Roots p) < card (BRoots p)
then consider a being Element of F such that
B:
multiplicity (p,a) > 1
;
set n = multiplicity (p,a);
consider q being Polynomial of F such that
C:
p = ((X- a) `^ (multiplicity (p,a))) *' q
by mulzero1, RING_4:1;
reconsider q = q as non zero Polynomial of F by C;
D:
card (BRoots p) = (card (BRoots ((X- a) `^ (multiplicity (p,a))))) + (card (BRoots q))
by C, RING_5:41;
J:
1 + (card (Roots q)) <= 1 + (card (BRoots q))
by RING_5:65, XREAL_1:6;
now not card (Roots p) = card (BRoots p)assume E:
card (Roots p) = card (BRoots p)
;
contradiction
Roots ((X- a) `^ (multiplicity (p,a))) = {a}
by B, Lm12b;
then F:
card (Roots ((X- a) `^ (multiplicity (p,a)))) = 1
by CARD_2:42;
Roots p = (Roots ((X- a) `^ (multiplicity (p,a)))) \/ (Roots q)
by C, UPROOTS:23;
then
(card (BRoots ((X- a) `^ (multiplicity (p,a))))) + (card (BRoots q)) <= 1
+ (card (Roots q))
by D, E, F, CARD_2:43;
then
(card (BRoots ((X- a) `^ (multiplicity (p,a))))) + (card (BRoots q)) <= 1
+ (card (BRoots q))
by J, XXREAL_0:2;
then
card (BRoots ((X- a) `^ (multiplicity (p,a)))) <= 1
by XREAL_1:6;
hence
contradiction
by B, caBR;
verum end;
hence
card (Roots p) < card (BRoots p)
by H, XXREAL_0:1; verum