let R be non degenerated Ring; for n being non zero Nat
for a, x being Element of R holds eval ((X^ (n,a)),x) = (x |^ n) - a
let n be non zero Nat; for a, x being Element of R holds eval ((X^ (n,a)),x) = (x |^ n) - a
let a, x be Element of R; eval ((X^ (n,a)),x) = (x |^ n) - a
set q = X^ (n,a);
consider F being FinSequence of R such that
A3:
eval ((X^ (n,a)),x) = Sum F
and
A4:
len F = len (X^ (n,a))
and
A5:
for j being Element of NAT st j in dom F holds
F . j = ((X^ (n,a)) . (j -' 1)) * ((power R) . (x,(j -' 1)))
by POLYNOM4:def 2;
A: n =
deg (X^ (n,a))
by Lm12
.=
(len (X^ (n,a))) - 1
by HURWITZ:def 2
;
then B:
len (X^ (n,a)) = n + 1
;
C:
dom F = Seg (n + 1)
by A, A4, FINSEQ_1:def 3;
D:
1 <= n + 1
by NAT_1:11;
E:
(n + 1) -' 1 = (n + 1) - 1
by NAT_1:11, XREAL_1:233;
B1: F . (n + 1) =
((X^ (n,a)) . n) * ((power R) . (x,((n + 1) -' 1)))
by E, A5, D, C, FINSEQ_1:1
.=
(1. R) * ((power R) . (x,((n + 1) -' 1)))
by Lm10
.=
x |^ n
by E
;
B2:
now for j being Element of NAT st 1 < j & j <= n holds
F . j = 0. Rlet j be
Element of
NAT ;
( 1 < j & j <= n implies F . j = 0. R )assume H0:
( 1
< j &
j <= n )
;
F . j = 0. Rreconsider j1 =
j -' 1 as
Element of
NAT ;
reconsider n1 =
n - 1 as
Element of
NAT by INT_1:3;
n <= n + 1
by NAT_1:11;
then H1:
j <= n + 1
by H0, XXREAL_0:2;
H4:
j1 = j - 1
by H0, XREAL_1:233;
then H2:
j1 <> 0
by H0;
j1 + 1
<= n1 + 1
by H4, H0;
then H3:
j1 <> n
by NAT_1:13;
thus F . j =
((X^ (n,a)) . j1) * ((power R) . (x,(j -' 1)))
by A5, H1, C, H0, FINSEQ_1:1
.=
(0. R) * ((power R) . (x,(j -' 1)))
by H2, H3, Lm11
.=
0. R
;
verum end;
B3: F . 1 =
((X^ (n,a)) . (1 -' 1)) * ((power R) . (x,(1 -' 1)))
by A5, C, D, FINSEQ_1:1
.=
((X^ (n,a)) . 0) * ((power R) . (x,(1 -' 1)))
by NAT_2:8
.=
((X^ (n,a)) . 0) * ((power R) . (x,0))
by NAT_2:8
.=
(- a) * ((power R) . (x,0))
by Lm10
.=
(- a) * (1_ R)
by GROUP_1:def 7
.=
- a
;
B4:
len F <> 0
by A, A4;
consider fp being sequence of the carrier of R such that
A6:
Sum F = fp . (len F)
and
A7:
fp . 0 = 0. R
and
A8:
for j being Nat
for v being Element of R st j < len F & v = F . (j + 1) holds
fp . (j + 1) = (fp . j) + v
by RLVECT_1:def 12;
defpred S1[ Element of NAT ] means ( ( $1 = 0 & fp . $1 = 0. R ) or ( 0 < $1 & $1 < len F & fp . $1 = - a ) or ( $1 = len F & fp . $1 = (x |^ n) - a ) );
IA:
S1[ 0 ]
by A7;
IS:
now for j being Element of NAT st 0 <= j & j < len F & S1[j] holds
S1[j + 1]let j be
Element of
NAT ;
( 0 <= j & j < len F & S1[j] implies S1[b1 + 1] )assume C1:
(
0 <= j &
j < len F )
;
( S1[j] implies S1[b1 + 1] )assume C2:
S1[
j]
;
S1[b1 + 1]per cases
( ( j = 0 & j < (len F) - 1 ) or ( j = 0 & j >= (len F) - 1 ) or ( 0 < j & j < (len F) - 1 ) or ( 0 < j & j >= (len F) - 1 ) )
;
suppose D1:
(
0 < j &
j < (len F) - 1 )
;
S1[b1 + 1]then D3:
j + 1
<= n
by A, A4, INT_1:7;
j + 1
> 0 + 1
by D1, XREAL_1:8;
then
F . (j + 1) = 0. R
by D3, B2;
then
fp . (j + 1) = (- a) + (0. R)
by C2, D1, C1, A8;
hence
S1[
j + 1]
by D3, B, A4, XXREAL_0:2, NAT_1:16;
verum end; suppose D1:
(
0 < j &
j >= (len F) - 1 )
;
S1[b1 + 1]
j + 1
<= len F
by INT_1:7, C1;
then D2:
(j + 1) - 1
<= (len F) - 1
by XREAL_1:9;
then
j = n
by A4, A, D1, XXREAL_0:1;
then
fp . (j + 1) = (fp . j) + (x |^ n)
by B1, A8, C1;
hence
S1[
j + 1]
by A4, A, B1, C2, D2, D1, XXREAL_0:1;
verum end; end; end;
I:
for j being Element of NAT st 0 <= j & j <= len F holds
S1[j]
from INT_1:sch 7(IA, IS);
thus
eval ((X^ (n,a)),x) = (x |^ n) - a
by I, A6, A3, B4; verum