let E be F -finite FieldExtension of F; E is F -simple
consider T being finite F -algebraic Subset of E such that
A:
E == FAdj (F,T)
by FIELD_7:37;
defpred S1[ Nat] means for E being F -finite FieldExtension of F
for T being finite F -algebraic Subset of E st card T = F & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T);
I:
for k being Nat st ( for n being Nat st n < k holds
S1[n] ) holds
S1[k]
proof
let k be
Nat;
( ( for n being Nat st n < k holds
S1[n] ) implies S1[k] )
assume B0:
for
n being
Nat st
n < k holds
S1[
n]
;
S1[k]
(
k <= 2 implies not not
k = 0 & ... & not
k = 2 )
;
per cases then
( k = 0 or k = 1 or k = 2 or k > 2 )
;
suppose B1:
k = 0
;
S1[k]now for E being F -finite FieldExtension of F
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let E be
F -finite FieldExtension of
F;
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let T be
finite F -algebraic Subset of
E;
( card T = k & E == FAdj (F,T) implies ex p being Element of E st FAdj (F,{p}) = FAdj (F,T) )assume
(
card T = k &
E == FAdj (
F,
T) )
;
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)then
T c= the
carrier of
F
by B1;
then B2:
FAdj (
F,
T)
== F
by FIELD_7:3;
reconsider F1 =
F as
FieldExtension of
F by FIELD_4:6;
set a = the
F -algebraic Element of
F1;
F is
Subfield of
E
by FIELD_4:7;
then
the
carrier of
F c= the
carrier of
E
by EC_PF_1:def 1;
then reconsider a1 = the
F -algebraic Element of
F1 as
Element of
E ;
B3:
FAdj (
F,
{a1})
= FAdj (
F,
{ the F -algebraic Element of F1})
by FIELD_10:9;
FAdj (
F,
{ the F -algebraic Element of F1})
== F
by FIELD_7:3;
hence
ex
p being
Element of
E st
FAdj (
F,
{p})
= FAdj (
F,
T)
by B2, B3;
verum end; hence
S1[
k]
;
verum end; suppose B1:
k = 1
;
S1[k]now for E being F -finite FieldExtension of F
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let E be
F -finite FieldExtension of
F;
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let T be
finite F -algebraic Subset of
E;
( card T = k & E == FAdj (F,T) implies ex p being Element of E st FAdj (F,{p}) = FAdj (F,T) )assume
(
card T = k &
E == FAdj (
F,
T) )
;
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)then consider a being
object such that B2:
T = {a}
by B1, CARD_2:42;
a in T
by B2, TARSKI:def 1;
then reconsider a1 =
a as
Element of
E ;
FAdj (
F,
{a1})
= FAdj (
F,
T)
by B2;
hence
ex
p being
Element of
E st
FAdj (
F,
{p})
= FAdj (
F,
T)
;
verum end; hence
S1[
k]
;
verum end; suppose B1:
k = 2
;
S1[k]now for E being F -finite FieldExtension of F
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let E be
F -finite FieldExtension of
F;
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let T be
finite F -algebraic Subset of
E;
( card T = k & E == FAdj (F,T) implies ex p being Element of E st FAdj (F,{p}) = FAdj (F,T) )assume
(
card T = k &
E == FAdj (
F,
T) )
;
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)then consider a,
b being
object such that B2:
(
a <> b &
T = {a,b} )
by B1, CARD_2:60;
(
a in {a,b} &
b in {a,b} )
by TARSKI:def 2;
then reconsider a =
a,
b =
b as
Element of
E by B2;
consider x being
Element of
F such that B3:
FAdj (
F,
{a,b})
= FAdj (
F,
{(a + ((@ (x,E)) * b))})
by simpA;
thus
ex
p being
Element of
E st
FAdj (
F,
{p})
= FAdj (
F,
T)
by B3, B2;
verum end; hence
S1[
k]
;
verum end; suppose B1:
k > 2
;
S1[k]now for E being F -finite FieldExtension of F
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let E be
F -finite FieldExtension of
F;
for T being finite F -algebraic Subset of E st card T = k & E == FAdj (F,T) holds
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)let T be
finite F -algebraic Subset of
E;
( card T = k & E == FAdj (F,T) implies ex p being Element of E st FAdj (F,{p}) = FAdj (F,T) )assume B2:
(
card T = k &
E == FAdj (
F,
T) )
;
ex p being Element of E st FAdj (F,{p}) = FAdj (F,T)set a = the
Element of
T;
(
T <> {} &
T c= the
carrier of
E )
by B1, B2;
then reconsider a = the
Element of
T as
Element of
E ;
reconsider T1 =
T \ {a} as
finite F -algebraic Subset of
E ;
reconsider k1 =
k - 1 as
Nat by B1;
then
{a} c= T
;
then B6:
T =
T \/ {a}
by XBOOLE_1:12
.=
T1 \/ {a}
by XBOOLE_1:39
;
a in {a}
by TARSKI:def 1;
then
not
a in T1
by XBOOLE_0:def 5;
then B9:
card T = (card T1) + 1
by B6, CARD_2:41;
set E1 =
FAdj (
F,
T1);
reconsider T2 =
T1 as
finite F -algebraic Subset of
(FAdj (F,T1)) by FIELD_6:35;
B11:
E is
FAdj (
F,
T1)
-extending
by FIELD_4:7;
then B10:
FAdj (
F,
T2)
= FAdj (
F,
T1)
by FIELD_13:19;
then consider q1 being
Element of
(FAdj (F,T1)) such that B8:
FAdj (
F,
{q1})
= FAdj (
F,
T2)
by B0, B2, B9, NAT_1:19;
the
carrier of
(FAdj (F,T1)) c= the
carrier of
E
by EC_PF_1:def 1;
then reconsider q =
q1 as
Element of
E ;
consider x being
Element of
F such that B5:
FAdj (
F,
{q,a})
= FAdj (
F,
{(q + ((@ (x,E)) * a))})
by simpA;
FAdj (
F,
T) =
FAdj (
F,
({q} \/ {a}))
by B6, B8, B10, B11, FIELD_13:19, simp1
.=
FAdj (
F,
{q,a})
by ENUMSET1:1
;
hence
ex
p being
Element of
E st
FAdj (
F,
{p})
= FAdj (
F,
T)
by B5;
verum end; hence
S1[
k]
;
verum end; end;
end;
J:
for n being Nat holds S1[n]
from NAT_1:sch 4(I);
consider n being Nat such that
K:
card T = n
;
consider p being Element of E such that
L:
FAdj (F,{p}) = FAdj (F,T)
by A, J, K;
thus
E is F -simple
by A, L; verum