let a, b be Element of NAT ; GenFib (a,a,b) = ((GenFib (a,a,0)) / 2) * ((Fib b) + (Lucas b))
defpred S1[ Nat] means GenFib (a,a,$1) = ((GenFib (a,a,0)) / 2) * ((Fib $1) + (Lucas $1));
A1:
for k being Nat st S1[k] & S1[k + 1] holds
S1[k + 2]
proof
let k be
Nat;
( S1[k] & S1[k + 1] implies S1[k + 2] )
assume that A2:
S1[
k]
and A3:
S1[
k + 1]
;
S1[k + 2]
GenFib (
a,
a,
(k + 2)) =
(((GenFib (a,a,0)) / 2) * ((Fib k) + (Lucas k))) + (GenFib (a,a,(k + 1)))
by A2, Th34
.=
((GenFib (a,a,0)) / 2) * (((Fib k) + (Fib (k + 1))) + ((Lucas k) + (Lucas (k + 1))))
by A3
.=
((GenFib (a,a,0)) / 2) * ((Fib (k + 2)) + ((Lucas k) + (Lucas (k + 1))))
by FIB_NUM2:24
.=
((GenFib (a,a,0)) / 2) * ((Fib (k + 2)) + (Lucas (k + 2)))
by Th12
;
hence
S1[
k + 2]
;
verum
end;
GenFib (a,a,1) = a
by Th32;
then A4:
S1[1]
by Th11, Th32, PRE_FF:1;
A5:
S1[ 0 ]
by Th11, PRE_FF:1;
for k being Nat holds S1[k]
from FIB_NUM:sch 1(A5, A4, A1);
hence
GenFib (a,a,b) = ((GenFib (a,a,0)) / 2) * ((Fib b) + (Lucas b))
; verum