defpred S1[ Nat] means for m, n being Nat st m <= $1 & n <= $1 holds
P1[m,n];
A3:
for k being Nat st ( for r being Nat st r < k holds
S1[r] ) holds
S1[k]
proof
let k be
Nat;
( ( for r being Nat st r < k holds
S1[r] ) implies S1[k] )
assume A4:
for
r being
Nat st
r < k holds
S1[
r]
;
S1[k]
let m,
n be
Nat;
( m <= k & n <= k implies P1[m,n] )
assume that A5:
m <= k
and A6:
n <= k
;
P1[m,n]
set s =
max (
m,
n);
A0:
max (
m,
n) is
Nat
by TARSKI:1;
A7:
max (
m,
n)
<= k
by A5, A6, XXREAL_0:28;
per cases
( max (m,n) < k or max (m,n) = k )
by A7, XXREAL_0:1;
suppose A8:
max (
m,
n)
= k
;
P1[m,n]A9:
for
m,
n being
Nat st
m < k &
n < k holds
P1[
m,
n]
proof
let m,
n be
Nat;
( m < k & n < k implies P1[m,n] )
assume that A10:
m < k
and A11:
n < k
;
P1[m,n]
set s =
max (
m,
n);
A0:
max (
m,
n) is
Nat
by TARSKI:1;
A12:
m <= max (
m,
n)
by XXREAL_0:25;
A13:
n <= max (
m,
n)
by XXREAL_0:25;
max (
m,
n)
< k
by A10, A11, XXREAL_0:16;
hence
P1[
m,
n]
by A4, A0, A12, A13;
verum
end; thus
P1[
m,
n]
verum end; end;
end;
A14:
for k being Nat holds S1[k]
from NAT_1:sch 4(A3);
let m, n be Nat; P1[m,n]
set k = max (m,n);
max (m,n) is Nat
by TARSKI:1;
then
( m <= max (m,n) & n <= max (m,n) implies P1[m,n] )
by A14;
hence
P1[m,n]
by XXREAL_0:30; verum