let Z be open Subset of REAL; :: thesis: ( Z c= dom (sec * sin) implies ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2) ) ) )

assume A1: Z c= dom (sec * sin) ; :: thesis: ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2) ) )

A2: for x being Real st x in Z holds
cos . (sin . x) <> 0
proof
let x be Real; :: thesis: ( x in Z implies cos . (sin . x) <> 0 )
assume x in Z ; :: thesis: cos . (sin . x) <> 0
then sin . x in dom sec by A1, FUNCT_1:11;
hence cos . (sin . x) <> 0 by RFUNCT_1:3; :: thesis: verum
end;
A3: for x being Real st x in Z holds
sec * sin is_differentiable_in x
proof end;
then A4: sec * sin is_differentiable_on Z by A1, FDIFF_1:9;
for x being Real st x in Z holds
((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2)
proof
let x be Real; :: thesis: ( x in Z implies ((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2) )
assume A5: x in Z ; :: thesis: ((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2)
then A6: cos . (sin . x) <> 0 by A2;
then ( sin is_differentiable_in x & sec is_differentiable_in sin . x ) by Th1, SIN_COS:64;
then diff ((sec * sin),x) = (diff (sec,(sin . x))) * (diff (sin,x)) by FDIFF_2:13
.= ((sin . (sin . x)) / ((cos . (sin . x)) ^2)) * (diff (sin,x)) by A6, Th1
.= (cos . x) * ((sin . (sin . x)) / ((cos . (sin . x)) ^2)) by SIN_COS:64 ;
hence ((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2) by A4, A5, FDIFF_1:def 7; :: thesis: verum
end;
hence ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2) ) ) by A1, A3, FDIFF_1:9; :: thesis: verum