let Z be open Subset of REAL; ( Z c= dom ((#Z 2) * (sin / cos)) & ( for x being Real st x in Z holds
cos . x <> 0 ) implies ( (#Z 2) * (sin / cos) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3) ) ) )
assume that
A1:
Z c= dom ((#Z 2) * (sin / cos))
and
A2:
for x being Real st x in Z holds
cos . x <> 0
; ( (#Z 2) * (sin / cos) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3) ) )
for y being object st y in Z holds
y in dom (sin / cos)
by A1, FUNCT_1:11;
then A3:
Z c= dom (sin / cos)
by TARSKI:def 3;
A4:
for x being Real st x in Z holds
(#Z 2) * (sin / cos) is_differentiable_in x
then A5:
(#Z 2) * (sin / cos) is_differentiable_on Z
by A1, FDIFF_1:9;
for x being Real st x in Z holds
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3)
proof
let x be
Real;
( x in Z implies (((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3) )
assume A6:
x in Z
;
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3)
then A7:
(sin / cos) . x =
(sin . x) * ((cos . x) ")
by A3, RFUNCT_1:def 1
.=
(sin . x) * (1 / (cos . x))
by XCMPLX_1:215
.=
(sin . x) / (cos . x)
by XCMPLX_1:99
;
A8:
cos . x <> 0
by A2, A6;
then A9:
sin / cos is_differentiable_in x
by Th46;
(((#Z 2) * (sin / cos)) `| Z) . x =
diff (
((#Z 2) * (sin / cos)),
x)
by A5, A6, FDIFF_1:def 7
.=
(2 * (((sin / cos) . x) #Z (2 - 1))) * (diff ((sin / cos),x))
by A9, TAYLOR_1:3
.=
(2 * (((sin / cos) . x) #Z (2 - 1))) * (1 / ((cos . x) ^2))
by A8, Th46
.=
(2 * (((sin / cos) . x) #Z 1)) / ((cos . x) ^2)
by XCMPLX_1:99
.=
(2 * ((sin . x) / (cos . x))) / ((cos . x) ^2)
by A7, PREPOWER:35
.=
((2 * (sin . x)) / (cos . x)) / ((cos . x) ^2)
by XCMPLX_1:74
.=
(2 * (sin . x)) / ((cos . x) * ((cos . x) ^2))
by XCMPLX_1:78
.=
(2 * (sin . x)) / ((cos . x) * ((cos . x) #Z 2))
by Th1
.=
(2 * (sin . x)) / (((cos . x) #Z 1) * ((cos . x) #Z 2))
by PREPOWER:35
.=
(2 * (sin . x)) / ((cos . x) #Z (1 + 2))
by A2, A6, PREPOWER:44
.=
(2 * (sin . x)) / ((cos . x) #Z 3)
;
hence
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3)
;
verum
end;
hence
( (#Z 2) * (sin / cos) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (sin / cos)) `| Z) . x = (2 * (sin . x)) / ((cos . x) #Z 3) ) )
by A1, A4, FDIFF_1:9; verum