let x be Real; ( cos . x <> 0 implies ( sin / cos is_differentiable_in x & diff ((sin / cos),x) = 1 / ((cos . x) ^2) ) )
assume A1:
cos . x <> 0
; ( sin / cos is_differentiable_in x & diff ((sin / cos),x) = 1 / ((cos . x) ^2) )
A2:
( sin is_differentiable_in x & cos is_differentiable_in x )
by SIN_COS:63, SIN_COS:64;
then diff ((sin / cos),x) =
(((diff (sin,x)) * (cos . x)) - ((diff (cos,x)) * (sin . x))) / ((cos . x) ^2)
by A1, FDIFF_2:14
.=
(((cos . x) * (cos . x)) - ((diff (cos,x)) * (sin . x))) / ((cos . x) ^2)
by SIN_COS:64
.=
(((cos . x) * (cos . x)) - ((- (sin . x)) * (sin . x))) / ((cos . x) ^2)
by SIN_COS:63
.=
(((cos . x) * (cos . x)) + ((sin . x) * (sin . x))) / ((cos . x) ^2)
.=
1 / ((cos . x) ^2)
by SIN_COS:28
;
hence
( sin / cos is_differentiable_in x & diff ((sin / cos),x) = 1 / ((cos . x) ^2) )
by A2, A1, FDIFF_2:14; verum