let Z be open Subset of REAL; ( Z c= dom (sin * (arctan + arccot)) & Z c= ].(- 1),1.[ implies ( sin * (arctan + arccot) is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * (arctan + arccot)) `| Z) . x = 0 ) ) )
assume that
A1:
Z c= dom (sin * (arctan + arccot))
and
A2:
Z c= ].(- 1),1.[
; ( sin * (arctan + arccot) is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * (arctan + arccot)) `| Z) . x = 0 ) )
A3:
arctan + arccot is_differentiable_on Z
by A2, Th37;
A4:
for x being Real st x in Z holds
sin * (arctan + arccot) is_differentiable_in x
then A6:
sin * (arctan + arccot) is_differentiable_on Z
by A1, FDIFF_1:9;
for x being Real st x in Z holds
((sin * (arctan + arccot)) `| Z) . x = 0
proof
let x be
Real;
( x in Z implies ((sin * (arctan + arccot)) `| Z) . x = 0 )
A7:
sin is_differentiable_in (arctan + arccot) . x
by SIN_COS:64;
assume A8:
x in Z
;
((sin * (arctan + arccot)) `| Z) . x = 0
then A9:
arctan + arccot is_differentiable_in x
by A3, FDIFF_1:9;
((sin * (arctan + arccot)) `| Z) . x =
diff (
(sin * (arctan + arccot)),
x)
by A6, A8, FDIFF_1:def 7
.=
(diff (sin,((arctan + arccot) . x))) * (diff ((arctan + arccot),x))
by A9, A7, FDIFF_2:13
.=
(cos . ((arctan + arccot) . x)) * (diff ((arctan + arccot),x))
by SIN_COS:64
.=
(cos . ((arctan + arccot) . x)) * (((arctan + arccot) `| Z) . x)
by A3, A8, FDIFF_1:def 7
.=
(cos . ((arctan + arccot) . x)) * 0
by A2, A8, Th37
.=
0
;
hence
((sin * (arctan + arccot)) `| Z) . x = 0
;
verum
end;
hence
( sin * (arctan + arccot) is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * (arctan + arccot)) `| Z) . x = 0 ) )
by A1, A4, FDIFF_1:9; verum