let p1, p2, p3, p4, p5, p6 be Point of (TOP-REAL 2); ( p3 <> p2 & p3 <> p1 & p2 <> p1 & p4 <> p5 & p4 <> p6 & p5 <> p6 & angle (p1,p2,p3) <> PI & angle (p2,p3,p1) <> PI & angle (p3,p1,p2) <> PI & angle (p4,p5,p6) <> PI & angle (p5,p6,p4) <> PI & angle (p6,p4,p5) <> PI & angle (p1,p2,p3) = angle (p4,p5,p6) & angle (p3,p1,p2) = angle (p5,p6,p4) implies |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).| )
assume that
A1:
( p3 <> p2 & p3 <> p1 )
and
A2:
p2 <> p1
; ( not p4 <> p5 or not p4 <> p6 or not p5 <> p6 or not angle (p1,p2,p3) <> PI or not angle (p2,p3,p1) <> PI or not angle (p3,p1,p2) <> PI or not angle (p4,p5,p6) <> PI or not angle (p5,p6,p4) <> PI or not angle (p6,p4,p5) <> PI or not angle (p1,p2,p3) = angle (p4,p5,p6) or not angle (p3,p1,p2) = angle (p5,p6,p4) or |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).| )
A3:
( euc2cpx p3 <> euc2cpx p2 & euc2cpx p3 <> euc2cpx p1 )
by A1, EUCLID_3:4;
A4:
euc2cpx p2 <> euc2cpx p1
by A2, EUCLID_3:4;
assume that
A5:
( p4 <> p5 & p4 <> p6 )
and
A6:
p5 <> p6
; ( not angle (p1,p2,p3) <> PI or not angle (p2,p3,p1) <> PI or not angle (p3,p1,p2) <> PI or not angle (p4,p5,p6) <> PI or not angle (p5,p6,p4) <> PI or not angle (p6,p4,p5) <> PI or not angle (p1,p2,p3) = angle (p4,p5,p6) or not angle (p3,p1,p2) = angle (p5,p6,p4) or |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).| )
A7:
( euc2cpx p4 <> euc2cpx p5 & euc2cpx p4 <> euc2cpx p6 )
by A5, EUCLID_3:4;
A8:
euc2cpx p5 <> euc2cpx p6
by A6, EUCLID_3:4;
assume A9:
( angle (p1,p2,p3) <> PI & angle (p2,p3,p1) <> PI & angle (p3,p1,p2) <> PI )
; ( not angle (p4,p5,p6) <> PI or not angle (p5,p6,p4) <> PI or not angle (p6,p4,p5) <> PI or not angle (p1,p2,p3) = angle (p4,p5,p6) or not angle (p3,p1,p2) = angle (p5,p6,p4) or |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).| )
assume that
A10:
angle (p4,p5,p6) <> PI
and
A11:
angle (p5,p6,p4) <> PI
and
A12:
angle (p6,p4,p5) <> PI
; ( not angle (p1,p2,p3) = angle (p4,p5,p6) or not angle (p3,p1,p2) = angle (p5,p6,p4) or |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).| )
assume that
A13:
angle (p1,p2,p3) = angle (p4,p5,p6)
and
A14:
angle (p3,p1,p2) = angle (p5,p6,p4)
; |.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|
A15: (sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))) =
(sin (angle (p4,p5,p6))) * (- (sin (angle (p5,p6,p4))))
by A13, Th2
.=
(- (sin (angle (p6,p5,p4)))) * (- (sin (angle (p3,p1,p2))))
by A14, Th2
.=
(sin (angle (p6,p5,p4))) * (sin (angle (p3,p1,p2)))
;
per cases
( (sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))) <> 0 or (sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))) = 0 )
;
suppose A16:
(sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))) <> 0
;
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|A17:
|.(p4 - p5).| * (sin (angle (p6,p5,p4))) = |.(p4 - p6).| * (sin (angle (p4,p6,p5)))
by A6, Th6;
A18:
((|.(p3 - p2).| * |.(p4 - p6).|) * (sin (angle (p1,p2,p3)))) * (sin (angle (p4,p6,p5))) =
(|.(p3 - p2).| * (sin (angle (p1,p2,p3)))) * (|.(p4 - p6).| * (sin (angle (p4,p6,p5))))
.=
(|.(p3 - p1).| * (sin (angle (p3,p1,p2)))) * (|.(p4 - p5).| * (sin (angle (p6,p5,p4))))
by A2, A17, Th6
.=
((|.(p3 - p1).| * |.(p4 - p5).|) * (sin (angle (p6,p5,p4)))) * (sin (angle (p3,p1,p2)))
;
thus |.(p2 - p3).| * |.(p4 - p6).| =
|.(p3 - p2).| * |.(p4 - p6).|
by Lm2
.=
((|.(p3 - p2).| * |.(p4 - p6).|) * ((sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))))) / ((sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))))
by A16, XCMPLX_1:89
.=
((|.(p3 - p1).| * |.(p4 - p5).|) * ((sin (angle (p6,p5,p4))) * (sin (angle (p3,p1,p2))))) / ((sin (angle (p6,p5,p4))) * (sin (angle (p3,p1,p2))))
by A15, A18
.=
|.(p3 - p1).| * |.(p4 - p5).|
by A15, A16, XCMPLX_1:89
.=
|.(p3 - p1).| * |.(p5 - p4).|
by Lm2
;
verum end; suppose A19:
(sin (angle (p1,p2,p3))) * (sin (angle (p4,p6,p5))) = 0
;
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|per cases
( sin (angle (p1,p2,p3)) = 0 or sin (angle (p4,p6,p5)) = 0 )
by A19;
suppose A20:
sin (angle (p1,p2,p3)) = 0
;
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|
(
(2 * PI) * 0 <= angle (
p1,
p2,
p3) &
angle (
p1,
p2,
p3)
< (2 * PI) + ((2 * PI) * 0) )
by COMPLEX2:70;
then
(
angle (
p1,
p2,
p3)
= (2 * PI) * 0 or
angle (
p1,
p2,
p3)
= PI + ((2 * PI) * 0) )
by A20, SIN_COS6:21;
hence
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|
by A3, A4, A9, COMPLEX2:87;
verum end; suppose A21:
sin (angle (p4,p6,p5)) = 0
;
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|
(
(2 * PI) * 0 <= angle (
p4,
p6,
p5) &
angle (
p4,
p6,
p5)
< (2 * PI) + ((2 * PI) * 0) )
by COMPLEX2:70;
then
(
angle (
p4,
p6,
p5)
= (2 * PI) * 0 or
angle (
p4,
p6,
p5)
= PI + ((2 * PI) * 0) )
by A21, SIN_COS6:21;
then
( (
angle (
p6,
p5,
p4)
= 0 &
angle (
p5,
p4,
p6)
= PI ) or (
angle (
p6,
p5,
p4)
= PI &
angle (
p5,
p4,
p6)
= 0 ) )
by A7, A8, A11, COMPLEX2:82, COMPLEX2:87;
hence
|.(p2 - p3).| * |.(p4 - p6).| = |.(p3 - p1).| * |.(p5 - p4).|
by A10, A12, COMPLEX2:82;
verum end; end; end; end;