let A, B, C be Point of (TOP-REAL 2); ( A,B,C is_a_triangle implies ex D being Point of (TOP-REAL 2) st
( D in median (A,B,C) & D in median (B,C,A) & D in median (C,A,B) ) )
assume A1:
A,B,C is_a_triangle
; ex D being Point of (TOP-REAL 2) st
( D in median (A,B,C) & D in median (B,C,A) & D in median (C,A,B) )
set D = the_midpoint_of_the_segment (B,C);
set E = the_midpoint_of_the_segment (C,A);
set F = the_midpoint_of_the_segment (A,B);
then A3:
Line (A,(the_midpoint_of_the_segment (B,C))), Line (B,(the_midpoint_of_the_segment (C,A))), Line (C,(the_midpoint_of_the_segment (A,B))) are_concurrent
by A1, Th59;
reconsider rA = A, rD = the_midpoint_of_the_segment (B,C), rB = B, rC = C, rE = the_midpoint_of_the_segment (C,A), rF = the_midpoint_of_the_segment (A,B) as Element of REAL 2 by EUCLID:22;
( Line (rA,rD) = Line (A,(the_midpoint_of_the_segment (B,C))) & Line (rB,rE) = Line (B,(the_midpoint_of_the_segment (C,A))) & Line (rC,rF) = Line (C,(the_midpoint_of_the_segment (A,B))) )
by Th4;
then reconsider LAD = Line (A,(the_midpoint_of_the_segment (B,C))), LBE = Line (B,(the_midpoint_of_the_segment (C,A))), LCF = Line (C,(the_midpoint_of_the_segment (A,B))) as Subset of (REAL 2) ;
now ( Line (A,(the_midpoint_of_the_segment (B,C))) is_parallel_to Line (B,(the_midpoint_of_the_segment (C,A))) & Line (B,(the_midpoint_of_the_segment (C,A))) is_parallel_to Line (C,(the_midpoint_of_the_segment (A,B))) implies not Line (C,(the_midpoint_of_the_segment (A,B))) is_parallel_to Line (A,(the_midpoint_of_the_segment (B,C))) )assume A5:
(
Line (
A,
(the_midpoint_of_the_segment (B,C)))
is_parallel_to Line (
B,
(the_midpoint_of_the_segment (C,A))) &
Line (
B,
(the_midpoint_of_the_segment (C,A)))
is_parallel_to Line (
C,
(the_midpoint_of_the_segment (A,B))) &
Line (
C,
(the_midpoint_of_the_segment (A,B)))
is_parallel_to Line (
A,
(the_midpoint_of_the_segment (B,C))) )
;
contradiction
(
the_midpoint_of_the_segment (
A,
B)
= ((1 - (1 / 2)) * A) + ((1 / 2) * B) &
the_midpoint_of_the_segment (
B,
C)
= ((1 - (1 / 2)) * B) + ((1 / 2) * C) &
(1 - (1 / 2)) + (((1 / 2) * 1) / 2) <> 0 &
C,
A,
B is_a_triangle )
by A1, A2, MENELAUS:15;
hence
contradiction
by A5, MENELAUS:16;
verum end;
hence
ex D being Point of (TOP-REAL 2) st
( D in median (A,B,C) & D in median (B,C,A) & D in median (C,A,B) )
by A3, MENELAUS:def 1; verum