let a, b, r, s be Real; ( r <> s implies circle (a,b,r) misses circle (a,b,s) )
assume A1:
r <> s
; circle (a,b,r) misses circle (a,b,s)
per cases
( not r is positive or not s is positive or ( r is positive & s is positive ) )
;
suppose
( not
r is
positive or not
s is
positive )
;
circle (a,b,r) misses circle (a,b,s)per cases then
( r = 0 or r < 0 or s < 0 or s = 0 )
;
suppose A2:
r = 0
;
circle (a,b,r) misses circle (a,b,s)then A3:
circle (
a,
b,
r)
= {|[a,b]|}
by EUCLID10:36;
assume
circle (
a,
b,
r)
meets circle (
a,
b,
s)
;
contradictionthen consider p being
object such that A4:
p in circle (
a,
b,
r)
and A5:
p in circle (
a,
b,
s)
by XBOOLE_0:3;
p in { p where p is Point of (TOP-REAL 2) : |.(p - |[a,b]|).| = s }
by A5, JGRAPH_6:def 5;
then consider p1 being
Point of
(TOP-REAL 2) such that A6:
p = p1
and A7:
|.(p1 - |[a,b]|).| = s
;
s =
|.(|[a,b]| - |[a,b]|).|
by A6, A7, A4, A3, TARSKI:def 1
.=
0
by EUCLID_6:42
;
hence
contradiction
by A2, A1;
verum end; suppose A8:
s = 0
;
circle (a,b,r) misses circle (a,b,s)then A9:
circle (
a,
b,
s)
= {|[a,b]|}
by EUCLID10:36;
assume
circle (
a,
b,
r)
meets circle (
a,
b,
s)
;
contradictionthen consider p being
object such that A10:
p in circle (
a,
b,
s)
and A11:
p in circle (
a,
b,
r)
by XBOOLE_0:3;
p in { p where p is Point of (TOP-REAL 2) : |.(p - |[a,b]|).| = r }
by A11, JGRAPH_6:def 5;
then consider p1 being
Point of
(TOP-REAL 2) such that A12:
p = p1
and A13:
|.(p1 - |[a,b]|).| = r
;
r =
|.(|[a,b]| - |[a,b]|).|
by A12, A13, A10, A9, TARSKI:def 1
.=
0
by EUCLID_6:42
;
hence
contradiction
by A8, A1;
verum end; end; end; suppose
(
r is
positive &
s is
positive )
;
circle (a,b,r) misses circle (a,b,s)assume
circle (
a,
b,
r)
meets circle (
a,
b,
s)
;
contradictionthen consider p being
object such that A15:
p in circle (
a,
b,
r)
and A16:
p in circle (
a,
b,
s)
by XBOOLE_0:3;
p in { p where p is Point of (TOP-REAL 2) : |.(p - |[a,b]|).| = r }
by A15, JGRAPH_6:def 5;
then consider p1 being
Point of
(TOP-REAL 2) such that A17:
p = p1
and A18:
|.(p1 - |[a,b]|).| = r
;
p in { p where p is Point of (TOP-REAL 2) : |.(p - |[a,b]|).| = s }
by A16, JGRAPH_6:def 5;
then consider p2 being
Point of
(TOP-REAL 2) such that A19:
p = p2
and A20:
|.(p2 - |[a,b]|).| = s
;
thus
contradiction
by A17, A19, A18, A1, A20;
verum end; end;