let L be Element of line_of_REAL 2; not for x being Element of REAL 2 holds x in L
assume A1:
for x being Element of REAL 2 holds x in L
; contradiction
reconsider OO = |[0,0]|, Ox = |[1,0]|, Oy = |[0,1]| as Element of REAL 2 by EUCLID:22;
A2:
( OO in L & Ox in L & Oy in L )
by A1;
per cases
( L is being_line or ex x being Element of REAL 2 st L = {x} )
by Th6;
suppose
L is
being_line
;
contradictionthen
L = Line (
Ox,
Oy)
by A2, Th14, EUCLIDLP:30;
then
OO in { (((1 - lambda) * Ox) + (lambda * Oy)) where lambda is Real : verum }
by A1;
then consider lambda being
Real such that A3:
OO = ((1 - lambda) * Ox) + (lambda * Oy)
;
A4:
|[0,0]| =
((1 - lambda) * |[1,0]|) + (lambda * |[0,1]|)
by A3
.=
|[((1 - lambda) * 1),((1 - lambda) * 0)]| + (lambda * |[0,1]|)
by EUCLID:58
.=
|[(1 - lambda),0]| + |[(lambda * 0),(lambda * 1)]|
by EUCLID:58
.=
|[((1 - lambda) + 0),(0 + lambda)]|
by EUCLID:56
.=
|[(1 - lambda),lambda]|
;
(
|[0,0]| `1 = 0 &
|[0,0]| `2 = 0 &
|[(1 - lambda),lambda]| `1 = 1
- lambda &
|[(1 - lambda),lambda]| `2 = lambda )
by EUCLID:52;
hence
contradiction
by A4;
verum end; end;