let A, B, C, E be Point of (TOP-REAL 2); ( A,B,C is_a_triangle & angle (E,B,A) = (angle (C,B,A)) / 3 & angle (B,A,E) = (angle (B,A,C)) / 3 implies A,B,E is_a_triangle )
assume that
A1:
A,B,C is_a_triangle
and
A2:
angle (E,B,A) = (angle (C,B,A)) / 3
and
A3:
angle (B,A,E) = (angle (B,A,C)) / 3
; A,B,E is_a_triangle
A4:
A,B,C are_mutually_distinct
by A1, EUCLID_6:20;
A5:
( angle (C,B,A) <> 0 & angle (B,A,C) <> 0 )
by A1, EUCLID10:30;
now ( A,B,E are_mutually_distinct & not angle (A,B,E) = PI & not angle (B,E,A) = PI & not angle (E,A,B) = PI )thus
A,
B,
E are_mutually_distinct
by A4, A2, Th1, A3, A5;
( not angle (A,B,E) = PI & not angle (B,E,A) = PI & not angle (E,A,B) = PI )hereby ( not angle (B,E,A) = PI & not angle (E,A,B) = PI )
assume
angle (
A,
B,
E)
= PI
;
contradictionthen
(
B in LSeg (
A,
E) &
B <> A )
by A4, EUCLID_6:11;
then angle (
E,
A,
B) =
angle (
B,
A,
B)
by EUCLID_6:9
.=
0
by Th1
;
hence
contradiction
by A5, A3, EUCLID_3:36;
verum
end; hereby not angle (E,A,B) = PI
assume
angle (
B,
E,
A)
= PI
;
contradictionthen
(
E in LSeg (
B,
A) &
E <> B )
by Th1, A3, A5, EUCLID_6:11;
then angle (
A,
B,
E) =
angle (
E,
B,
E)
by EUCLID_6:9
.=
0
by Th1
;
hence
contradiction
by A5, A2, EUCLID_3:36;
verum
end; hereby verum
assume A6:
angle (
E,
A,
B)
= PI
;
contradictionthen A7:
angle (
B,
A,
E) =
(2 * PI) - (angle (E,A,B))
by COMPTRIG:5, EUCLID_3:37
.=
PI
by A6
;
(2 * PI) + 0 < (2 * PI) + PI
by XREAL_1:8, COMPTRIG:5;
hence
contradiction
by A7, A3, Th2;
verum
end; end;
hence
A,B,E is_a_triangle
by EUCLID_6:20; verum