let A, B, C, E, F be Point of (TOP-REAL 2); ( A,B,C is_a_triangle & A,B,E is_a_triangle & angle (E,B,A) = (angle (C,B,A)) / 3 & angle (B,A,E) = (angle (B,A,C)) / 3 & A,F,C is_a_triangle & angle (A,C,F) = (angle (A,C,B)) / 3 & angle (F,A,C) = (angle (B,A,C)) / 3 & angle (A,C,B) < PI implies |.(F - E).| = (((4 * (the_diameter_of_the_circumcircle (A,B,C))) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) * (sin ((angle (B,A,C)) / 3)) )
assume that
A1:
A,B,C is_a_triangle
and
A2:
A,B,E is_a_triangle
and
A3:
angle (E,B,A) = (angle (C,B,A)) / 3
and
A4:
angle (B,A,E) = (angle (B,A,C)) / 3
and
A5:
A,F,C is_a_triangle
and
A6:
angle (A,C,F) = (angle (A,C,B)) / 3
and
A7:
angle (F,A,C) = (angle (B,A,C)) / 3
and
A8:
angle (A,C,B) < PI
; |.(F - E).| = (((4 * (the_diameter_of_the_circumcircle (A,B,C))) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) * (sin ((angle (B,A,C)) / 3))
A9:
A,C,B is_a_triangle
by A1, MENELAUS:15;
then A10:
sin ((PI / 3) - ((angle (A,C,B)) / 3)) <> 0
by Th11;
C,B,A is_a_triangle
by A1, MENELAUS:15;
then A11:
sin ((PI / 3) - ((angle (C,B,A)) / 3)) <> 0
by Th11;
A12:
A,C,B are_mutually_distinct
by A9, EUCLID_6:20;
then
((angle (A,C,B)) + (angle (C,B,A))) + (angle (B,A,C)) = PI
by A8, EUCLID_3:47;
then A13:
(((angle (A,C,B)) / 3) + ((angle (B,A,C)) / 3)) + ((angle (C,B,A)) / 3) = PI / 3
;
angle (A,C,B) <> 0
by A1, EUCLID10:30;
then A14:
0 < angle (A,C,B)
by Th2;
then A15:
angle (C,B,A) < PI
by A12, A8, Th4;
angle (A,C,B) <> 0
by A1, EUCLID10:30;
then A16:
( 0 < angle (A,C,B) & angle (A,C,B) < PI & A,C,B are_mutually_distinct )
by A9, EUCLID_6:20, A8, Th2;
then
angle (B,A,C) < PI
by Th4;
then A17:
( (angle (B,A,C)) / 3 < PI / 3 & PI / 3 < PI )
by XREAL_1:74, XREAL_1:221, COMPTRIG:5;
A18:
( E,A,B is_a_triangle & B,A,E is_a_triangle & E,B,A is_a_triangle )
by A2, MENELAUS:15;
then A19:
( B,A,E are_mutually_distinct & E,B,A are_mutually_distinct & angle (E,B,A) <> 0 & angle (B,A,E) <> 0 )
by EUCLID_6:20, EUCLID10:30;
( 0 < angle (B,A,E) & angle (B,A,E) < PI )
by A17, A4, XXREAL_0:2, A19, Th2;
then A20:
angle (A,E,B) < PI
by A19, Th4;
F,A,C is_a_triangle
by A5, MENELAUS:15;
then A21:
( F,A,C are_mutually_distinct & angle (F,A,C) <> 0 )
by EUCLID_6:20, EUCLID10:30;
then
( 0 < angle (F,A,C) & angle (F,A,C) < PI )
by A17, A7, XXREAL_0:2, Th2;
then A22:
angle (C,F,A) < PI
by A21, Th4;
A23:
F,A,E is_a_triangle
proof
now ( F,A,E are_mutually_distinct & angle (F,A,E) <> PI & angle (A,E,F) <> PI & angle (E,F,A) <> PI )
E <> F
proof
assume A24:
E = F
;
contradiction
per cases
( (angle (B,A,E)) + (angle (E,A,C)) = angle (B,A,C) or (angle (B,A,E)) + (angle (E,A,C)) = (angle (B,A,C)) + (2 * PI) )
by EUCLID_6:4;
suppose A25:
(angle (B,A,E)) + (angle (E,A,C)) = angle (
B,
A,
C)
;
contradictionA26:
0 < angle (
B,
A,
C)
by A16, Th4;
then A27:
(angle (B,A,C)) / (angle (B,A,C)) = 1
by XCMPLX_1:60;
(angle (B,A,C)) / (angle (B,A,C)) =
((2 / 3) * (angle (B,A,C))) / (angle (B,A,C))
by A24, A7, A4, A25
.=
2
/ 3
by A27
;
hence
contradiction
by A26, XCMPLX_1:60;
verum end; end;
end; hence
F,
A,
E are_mutually_distinct
by A21, A19;
( angle (F,A,E) <> PI & angle (A,E,F) <> PI & angle (E,F,A) <> PI )now ( not angle (F,A,E) = PI & not angle (A,E,F) = PI & not angle (E,F,A) = PI )hereby ( not angle (A,E,F) = PI & not angle (E,F,A) = PI )
assume A30:
angle (
F,
A,
E)
= PI
;
contradictionA31:
(
(angle (C,A,F)) + (angle (F,A,E)) = angle (
C,
A,
E) or
(angle (C,A,F)) + (angle (F,A,E)) = (angle (C,A,E)) + (2 * PI) )
by EUCLID_6:4;
per cases
( (angle (C,A,E)) + (angle (E,A,B)) = angle (C,A,B) or (angle (C,A,E)) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI) )
by EUCLID_6:4;
suppose
(angle (C,A,E)) + (angle (E,A,B)) = angle (
C,
A,
B)
;
contradictionper cases then
( ((angle (C,A,F)) + PI) + (angle (E,A,B)) = angle (C,A,B) or ((angle (C,A,F)) - PI) + (angle (E,A,B)) = angle (C,A,B) )
by A31, A30;
suppose A32:
((angle (C,A,F)) + PI) + (angle (E,A,B)) = angle (
C,
A,
B)
;
contradictionA33:
0 < angle (
B,
A,
C)
by A16, Th4;
A34:
((angle (C,A,F)) + PI) + (angle (E,A,B)) = (2 * PI) - (angle (B,A,C))
by A32, A1, EUCLID10:31;
A35:
angle (
C,
A,
F)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A7, A5, EUCLID10:31;
(
angle (
E,
A,
B)
= (2 * PI) - (angle (B,A,E)) &
(2 * PI) - (angle (B,A,E)) = (2 * PI) - ((angle (B,A,C)) / 3) )
by A4, A2, EUCLID10:31;
then
3
* PI = - ((1 / 3) * (angle (B,A,C)))
by A34, A35;
hence
contradiction
by A33, COMPTRIG:5;
verum end; suppose A36:
((angle (C,A,F)) - PI) + (angle (E,A,B)) = angle (
C,
A,
B)
;
contradictionA37:
0 < angle (
B,
A,
C)
by A16, Th4;
A38:
((angle (C,A,F)) - PI) + (angle (E,A,B)) = (2 * PI) - (angle (B,A,C))
by A36, A1, EUCLID10:31;
A39:
(
angle (
C,
A,
F)
= (2 * PI) - (angle (F,A,C)) &
(2 * PI) - (angle (F,A,C)) = (2 * PI) - ((angle (B,A,C)) / 3) )
by A7, A5, EUCLID10:31;
angle (
E,
A,
B)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A4, A2, EUCLID10:31;
hence
contradiction
by A37, COMPTRIG:5, A38, A39;
verum end; end; end; suppose
(angle (C,A,E)) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI)
;
contradictionper cases then
( ((angle (C,A,F)) + PI) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI) or ((angle (C,A,F)) - PI) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI) )
by A31, A30;
suppose A40:
((angle (C,A,F)) + PI) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI)
;
contradictionA41:
0 < angle (
B,
A,
C)
by A16, Th4;
A42:
((angle (C,A,F)) + PI) + (angle (E,A,B)) = ((2 * PI) - (angle (B,A,C))) + (2 * PI)
by A40, A1, EUCLID10:31;
A43:
angle (
C,
A,
F)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A7, A5, EUCLID10:31;
angle (
E,
A,
B)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A4, A2, EUCLID10:31;
hence
contradiction
by A42, A43, A41, COMPTRIG:5;
verum end; suppose A44:
((angle (C,A,F)) - PI) + (angle (E,A,B)) = (angle (C,A,B)) + (2 * PI)
;
contradictionA45:
((angle (C,A,F)) - PI) + (angle (E,A,B)) = ((2 * PI) - (angle (B,A,C))) + (2 * PI)
by A44, A1, EUCLID10:31;
A46:
angle (
C,
A,
F)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A7, A5, EUCLID10:31;
angle (
E,
A,
B)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A4, A2, EUCLID10:31;
then
( 3
* PI = ((3 * 1) / 3) * (angle (B,A,C)) &
(2 * PI) + 0 < (2 * PI) + PI )
by A45, A46, XREAL_1:6, COMPTRIG:5;
hence
contradiction
by Th2;
verum end; end; end; end;
end; hereby not angle (E,F,A) = PI
assume
angle (
A,
E,
F)
= PI
;
contradictionthen A47:
(
E in LSeg (
A,
F) &
E <> A )
by A19, EUCLID_6:11;
A48:
(
(angle (C,A,F)) + (angle (F,A,B)) = angle (
C,
A,
B) or
(angle (C,A,F)) + (angle (F,A,B)) = (angle (C,A,B)) + (2 * PI) )
by EUCLID_6:4;
A49:
angle (
C,
A,
F)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A7, A5, EUCLID10:31;
angle (
F,
A,
B) =
angle (
E,
A,
B)
by A47, EUCLID_6:9
.=
(2 * PI) - ((angle (B,A,C)) / 3)
by A4, A2, EUCLID10:31
;
per cases then
( (((2 * PI) - ((angle (B,A,C)) / 3)) + (2 * PI)) - ((angle (B,A,C)) / 3) = (2 * PI) - (angle (B,A,C)) or (((2 * PI) - ((angle (B,A,C)) / 3)) + (2 * PI)) - ((angle (B,A,C)) / 3) = ((2 * PI) - (angle (B,A,C))) + (2 * PI) )
by A1, EUCLID10:31, A48, A49;
end;
end; hereby verum
assume
angle (
E,
F,
A)
= PI
;
contradictionthen A51:
(
F in LSeg (
E,
A) &
F <> A )
by A21, EUCLID_6:11;
A52:
(
(angle (C,A,F)) + (angle (F,A,B)) = angle (
C,
A,
B) or
(angle (C,A,F)) + (angle (F,A,B)) = (angle (C,A,B)) + (2 * PI) )
by EUCLID_6:4;
A53:
angle (
C,
A,
F)
= (2 * PI) - ((angle (B,A,C)) / 3)
by A5, A7, EUCLID10:31;
angle (
F,
A,
B) =
angle (
E,
A,
B)
by A51, EUCLID_6:9
.=
(2 * PI) - ((angle (B,A,C)) / 3)
by A4, A2, EUCLID10:31
;
per cases then
( (((2 * PI) - ((angle (B,A,C)) / 3)) + (2 * PI)) - ((angle (B,A,C)) / 3) = (2 * PI) - (angle (B,A,C)) or (((2 * PI) - ((angle (B,A,C)) / 3)) + (2 * PI)) - ((angle (B,A,C)) / 3) = ((2 * PI) - (angle (B,A,C))) + (2 * PI) )
by A1, EUCLID10:31, A52, A53;
end;
end; end; hence
(
angle (
F,
A,
E)
<> PI &
angle (
A,
E,
F)
<> PI &
angle (
E,
F,
A)
<> PI )
;
verum end;
hence
F,
A,
E is_a_triangle
by EUCLID_6:20;
verum
end;
A55:
- (the_diameter_of_the_circumcircle (C,B,A)) = the_diameter_of_the_circumcircle (A,B,C)
by A1, EUCLID10:49;
set lambda = - ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)));
A56: |.(A - E).| =
- (((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((PI / 3) + ((angle (A,C,B)) / 3)))) * (sin ((angle (C,B,A)) / 3)))
by A1, A2, A3, A4, A15, A20, A10, EUCLID10:56
.=
(- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) * (sin ((PI / 3) + ((angle (A,C,B)) / 3)))
;
A57: |.(A - F).| =
((((the_diameter_of_the_circumcircle (A,B,C)) * 4) * (sin ((angle (C,B,A)) / 3))) * (sin ((PI / 3) + ((angle (C,B,A)) / 3)))) * (sin ((angle (A,C,B)) / 3))
by A1, A5, A6, A7, A11, A13, A22, Th8
.=
(- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) * (sin ((PI / 3) + ((angle (C,B,A)) / 3)))
by A55
;
A58:
C,A,B is_a_triangle
by A1, MENELAUS:15;
then A59:
(((PI / 3) + ((angle (A,C,B)) / 3)) + ((PI / 3) + ((angle (C,B,A)) / 3))) + (angle (E,A,F)) = PI
by Th10, A5, A23, A18, A4, A7, A8;
A60: |.(F - E).| ^2 =
((|.(A - E).| ^2) + (|.(A - F).| ^2)) - (((2 * |.(A - E).|) * |.(A - F).|) * (cos (angle (E,A,F))))
by Th3
.=
((- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) ^2) * ((((sin ((PI / 3) + ((angle (A,C,B)) / 3))) ^2) + ((sin ((PI / 3) + ((angle (C,B,A)) / 3))) ^2)) - (((2 * (sin ((PI / 3) + ((angle (A,C,B)) / 3)))) * (sin ((PI / 3) + ((angle (C,B,A)) / 3)))) * (cos (angle (E,A,F)))))
by A56, A57
.=
((- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) ^2) * ((sin (angle (E,A,F))) ^2)
by A59, EUCLID10:25
.=
((- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) ^2) * ((sin ((angle (B,A,C)) / 3)) ^2)
by Th9, A58, A5, A23, A18, A4, A7
.=
((- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) * (sin ((angle (B,A,C)) / 3))) ^2
;
now ( 0 <= - ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) & 0 <= sin ((angle (B,A,C)) / 3) )A61:
- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) =
(((- (the_diameter_of_the_circumcircle (C,B,A))) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))
.=
(((the_diameter_of_the_circumcircle (A,B,C)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))
by A1, EUCLID10:49
;
now ( sin ((angle (C,B,A)) / 3) >= 0 & 0 <= sin ((angle (A,C,B)) / 3) & 0 <= the_diameter_of_the_circumcircle (A,B,C) )
(
0 <= angle (
C,
B,
A) &
angle (
C,
B,
A)
< PI )
by A14, A12, A8, Th4;
then A62:
(
0 <= (angle (C,B,A)) / 3 &
(angle (C,B,A)) / 3
< PI / 3 )
by XREAL_1:74;
PI / 3
< PI / 1
by COMPTRIG:5, XREAL_1:76;
then
(
(2 * PI) * 0 <= (angle (C,B,A)) / 3 &
(angle (C,B,A)) / 3
< PI + ((2 * PI) * 0) )
by A62, XXREAL_0:2;
hence
sin ((angle (C,B,A)) / 3) >= 0
by SIN_COS6:16;
( 0 <= sin ((angle (A,C,B)) / 3) & 0 <= the_diameter_of_the_circumcircle (A,B,C) )
(
0 <= angle (
A,
C,
B) &
angle (
A,
C,
B)
< PI )
by A8, Th2;
then A63:
(
0 <= (angle (A,C,B)) / 3 &
(angle (A,C,B)) / 3
< PI / 3 )
by XREAL_1:74;
PI / 3
< PI / 1
by COMPTRIG:5, XREAL_1:76;
then
(
(2 * PI) * 0 <= (angle (A,C,B)) / 3 &
(angle (A,C,B)) / 3
< PI + ((2 * PI) * 0) )
by A63, XXREAL_0:2;
hence
0 <= sin ((angle (A,C,B)) / 3)
by SIN_COS6:16;
0 <= the_diameter_of_the_circumcircle (A,B,C)thus
0 <= the_diameter_of_the_circumcircle (
A,
B,
C)
by A15, Th6;
verum end; hence
0 <= - ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))
by A61;
0 <= sin ((angle (B,A,C)) / 3)now ( A,C,B are_mutually_distinct & 0 < angle (A,C,B) & angle (A,C,B) < PI )
A,
C,
B is_a_triangle
by A1, MENELAUS:15;
hence
A,
C,
B are_mutually_distinct
by EUCLID_6:20;
( 0 < angle (A,C,B) & angle (A,C,B) < PI )
angle (
A,
C,
B)
<> 0
by A1, EUCLID10:30;
hence
(
0 < angle (
A,
C,
B) &
angle (
A,
C,
B)
< PI )
by A8, Th2;
verum end; then
(
0 <= angle (
B,
A,
C) &
angle (
B,
A,
C)
< PI )
by Th4;
then A64:
(
0 <= (angle (B,A,C)) / 3 &
(angle (B,A,C)) / 3
< PI / 3 )
by XREAL_1:74;
PI / 3
< PI / 1
by COMPTRIG:5, XREAL_1:76;
then
(
(2 * PI) * 0 <= (angle (B,A,C)) / 3 &
(angle (B,A,C)) / 3
< PI + ((2 * PI) * 0) )
by A64, XXREAL_0:2;
hence
0 <= sin ((angle (B,A,C)) / 3)
by SIN_COS6:16;
verum end;
then A65:
sqrt (((- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) * (sin ((angle (B,A,C)) / 3))) ^2) = (- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3)))) * (sin ((angle (B,A,C)) / 3))
by SQUARE_1:22;
- ((((the_diameter_of_the_circumcircle (C,B,A)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) =
(((- (the_diameter_of_the_circumcircle (C,B,A))) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))
.=
(((the_diameter_of_the_circumcircle (A,B,C)) * 4) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))
by A1, EUCLID10:49
;
hence
|.(F - E).| = (((4 * (the_diameter_of_the_circumcircle (A,B,C))) * (sin ((angle (A,C,B)) / 3))) * (sin ((angle (C,B,A)) / 3))) * (sin ((angle (B,A,C)) / 3))
by A60, SQUARE_1:22, A65; verum