let A, B, C be Point of (TOP-REAL 2); ( A,B,C is_a_triangle implies ( |.(A - B).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (A,C,B))) & |.(B - C).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (B,A,C))) & |.(C - A).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (C,B,A))) ) )
assume A1:
A,B,C is_a_triangle
; ( |.(A - B).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (A,C,B))) & |.(B - C).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (B,A,C))) & |.(C - A).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (C,B,A))) )
then A2:
( B,C,A is_a_triangle & C,A,B is_a_triangle )
by MENELAUS:15;
A3:
|.(B - C).| = (the_diameter_of_the_circumcircle (B,C,A)) * (sin (angle (B,A,C)))
by A2, Lm10;
thus
|.(A - B).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (A,C,B)))
by A1, Lm10; ( |.(B - C).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (B,A,C))) & |.(C - A).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (C,B,A))) )
thus
|.(B - C).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (B,A,C)))
by A3, Thm27; |.(C - A).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (C,B,A)))
|.(C - A).| = (the_diameter_of_the_circumcircle (C,A,B)) * (sin (angle (C,B,A)))
by A2, Lm10;
hence
|.(C - A).| = (the_diameter_of_the_circumcircle (A,B,C)) * (sin (angle (C,B,A)))
by Thm27; verum