let X be set ; for EqR being Equivalence_Relation of X
for x, y being object holds
( not y in X or Class (EqR,x) = Class (EqR,y) or Class (EqR,x) misses Class (EqR,y) )
let EqR be Equivalence_Relation of X; for x, y being object holds
( not y in X or Class (EqR,x) = Class (EqR,y) or Class (EqR,x) misses Class (EqR,y) )
let x, y be object ; ( not y in X or Class (EqR,x) = Class (EqR,y) or Class (EqR,x) misses Class (EqR,y) )
A1:
( not [x,y] in EqR implies Class (EqR,x) misses Class (EqR,y) )
proof
assume A2:
not
[x,y] in EqR
;
Class (EqR,x) misses Class (EqR,y)
assume
Class (
EqR,
x)
meets Class (
EqR,
y)
;
contradiction
then consider z being
object such that A3:
z in Class (
EqR,
x)
and A4:
z in Class (
EqR,
y)
by XBOOLE_0:3;
[z,x] in EqR
by A3, Th19;
then A5:
[x,z] in EqR
by Th6;
[z,y] in EqR
by A4, Th19;
hence
contradiction
by A2, A5, Th7;
verum
end;
assume A6:
y in X
; ( Class (EqR,x) = Class (EqR,y) or Class (EqR,x) misses Class (EqR,y) )
( [x,y] in EqR implies Class (EqR,x) = Class (EqR,y) )
hence
( Class (EqR,x) = Class (EqR,y) or Class (EqR,x) misses Class (EqR,y) )
by A1; verum