let p, q be non empty ProbFinS FinSequence of REAL ; for pp, qq being FinSequence of REAL st len p = len q & len pp = len p & len qq = len q & ( for k being Nat st k in dom p holds
( p . k > 0 & q . k > 0 & pp . k = - ((p . k) * (log (2,(p . k)))) & qq . k = - ((p . k) * (log (2,(q . k)))) ) ) holds
( Sum pp <= Sum qq & ( ( for k being Nat st k in dom p holds
p . k = q . k ) implies Sum pp = Sum qq ) & ( Sum pp = Sum qq implies for k being Nat st k in dom p holds
p . k = q . k ) & ( ex k being Nat st
( k in dom p & p . k <> q . k ) implies Sum pp < Sum qq ) & ( Sum pp < Sum qq implies ex k being Nat st
( k in dom p & p . k <> q . k ) ) )
let pp, qq be FinSequence of REAL ; ( len p = len q & len pp = len p & len qq = len q & ( for k being Nat st k in dom p holds
( p . k > 0 & q . k > 0 & pp . k = - ((p . k) * (log (2,(p . k)))) & qq . k = - ((p . k) * (log (2,(q . k)))) ) ) implies ( Sum pp <= Sum qq & ( ( for k being Nat st k in dom p holds
p . k = q . k ) implies Sum pp = Sum qq ) & ( Sum pp = Sum qq implies for k being Nat st k in dom p holds
p . k = q . k ) & ( ex k being Nat st
( k in dom p & p . k <> q . k ) implies Sum pp < Sum qq ) & ( Sum pp < Sum qq implies ex k being Nat st
( k in dom p & p . k <> q . k ) ) ) )
assume that
A1:
len p = len q
and
A2:
len pp = len p
and
A3:
len qq = len q
and
A4:
for k being Nat st k in dom p holds
( p . k > 0 & q . k > 0 & pp . k = - ((p . k) * (log (2,(p . k)))) & qq . k = - ((p . k) * (log (2,(q . k)))) )
; ( Sum pp <= Sum qq & ( ( for k being Nat st k in dom p holds
p . k = q . k ) implies Sum pp = Sum qq ) & ( Sum pp = Sum qq implies for k being Nat st k in dom p holds
p . k = q . k ) & ( ex k being Nat st
( k in dom p & p . k <> q . k ) implies Sum pp < Sum qq ) & ( Sum pp < Sum qq implies ex k being Nat st
( k in dom p & p . k <> q . k ) ) )
set p1 = pp - qq;
A5:
number_e <> 1
by TAYLOR_1:11;
A6:
len (pp - qq) = len p
by A1, A2, A3, RVSUM_1:116;
then A7:
dom (pp - qq) = dom pp
by A2, FINSEQ_3:29;
then
for k being Nat st k in dom pp holds
(pp - qq) . k = (pp . k) - (qq . k)
by VALUED_1:13;
then A8:
(Sum pp) - (Sum qq) = Sum (pp - qq)
by A1, A2, A3, A6, Th8;
A9: dom pp =
Seg (len pp)
by FINSEQ_1:def 3
.=
dom p
by A2, FINSEQ_1:def 3
;
A10:
for k being Nat st k in dom p holds
(pp - qq) . k = ((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k))))
proof
let k be
Nat;
( k in dom p implies (pp - qq) . k = ((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k)))) )
assume A11:
k in dom p
;
(pp - qq) . k = ((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k))))
A12:
pp . k = - ((p . k) * (log (2,(p . k))))
by A4, A11;
A13:
qq . k = - ((p . k) * (log (2,(q . k))))
by A4, A11;
A14:
p . k > 0
by A4, A11;
then A15:
- (log (2,(p . k))) = log (2,
(1 / (p . k)))
by Th5;
A16:
q . k > 0
by A4, A11;
then
(q . k) / (p . k) > 0
by A14, XREAL_1:139;
then A17:
log (2,
((q . k) / (p . k)))
= (log (2,number_e)) * (log (number_e,((q . k) / (p . k))))
by A5, POWER:56, TAYLOR_1:11;
thus (pp - qq) . k =
(pp . k) - (qq . k)
by A7, A9, A11, VALUED_1:13
.=
(p . k) * ((log (2,(1 / (p . k)))) + (log (2,(q . k))))
by A12, A13, A15
.=
(p . k) * (log (2,((1 / (p . k)) * (q . k))))
by A14, A16, POWER:53
.=
((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k))))
by A17
;
verum
end;
set n = len p;
deffunc H1( Nat) -> Element of REAL = In ((((p . $1) * (log (2,number_e))) * (((q . $1) / (p . $1)) - 1)),REAL);
consider p2 being FinSequence of REAL such that
A18:
len p2 = len p
and
A19:
for k being Nat st k in dom p2 holds
p2 . k = H1(k)
from FINSEQ_2:sch 1();
A20: dom p2 =
Seg (len p2)
by FINSEQ_1:def 3
.=
dom p
by A18, FINSEQ_1:def 3
;
A21:
len (pp - qq) = len p
by A1, A2, A3, RVSUM_1:116;
then A22:
pp - qq is Element of (len p) -tuples_on REAL
by FINSEQ_2:92;
A23:
dom p2 = Seg (len p)
by A18, FINSEQ_1:def 3;
A24:
len (q - p) = len q
by A1, RVSUM_1:116;
A25:
for k being Nat st k in dom q holds
(q - p) . k = (q . k) - (p . k)
A26:
dom p = Seg (len p)
by FINSEQ_1:def 3;
A27:
dom (q - p) = dom p2
by A1, A18, A24, FINSEQ_3:29;
A28:
for k being Nat st k in dom p2 holds
p2 . k = ((log (2,number_e)) * (q - p)) . k
proof
let k be
Nat;
( k in dom p2 implies p2 . k = ((log (2,number_e)) * (q - p)) . k )
assume A29:
k in dom p2
;
p2 . k = ((log (2,number_e)) * (q - p)) . k
A30:
p . k > 0
by A4, A20, A29;
thus p2 . k =
H1(
k)
by A19, A29
.=
(log (2,number_e)) * ((((p . k) / (p . k)) * (q . k)) - (p . k))
.=
(log (2,number_e)) * ((1 * (q . k)) - (p . k))
by A30, XCMPLX_1:60
.=
(log (2,number_e)) * ((q - p) . k)
by A27, A29, VALUED_1:13
.=
((log (2,number_e)) * (q - p)) . k
by RVSUM_1:44
;
verum
end;
dom p2 = dom ((log (2,number_e)) * (q - p))
by A27, VALUED_1:def 5;
then A31: Sum p2 =
Sum ((log (2,number_e)) * (q - p))
by A28, FINSEQ_1:13
.=
(log (2,number_e)) * (Sum (q - p))
by RVSUM_1:87
.=
(log (2,number_e)) * ((Sum q) - (Sum p))
by A1, A24, A25, Th8
.=
(log (2,number_e)) * (1 - (Sum p))
by MATRPROB:def 5
.=
(log (2,number_e)) * (1 - 1)
by MATRPROB:def 5
.=
0
;
number_e - 0 > 2 - 1
by TAYLOR_1:11, XREAL_1:15;
then A32:
log (2,number_e) > 0
by Th4;
A33:
for k being Nat st k in Seg (len p) holds
(pp - qq) . k <= p2 . k
proof
let k be
Nat;
( k in Seg (len p) implies (pp - qq) . k <= p2 . k )
assume A34:
k in Seg (len p)
;
(pp - qq) . k <= p2 . k
A35:
k in dom p
by A34, FINSEQ_1:def 3;
then A36:
p . k > 0
by A4;
q . k > 0
by A4, A35;
then
(q . k) / (p . k) > 0
by A36, XREAL_1:139;
then
log (
number_e,
((q . k) / (p . k)))
<= ((q . k) / (p . k)) - 1
by Th3;
then
((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k)))) <= ((p . k) * (log (2,number_e))) * (((q . k) / (p . k)) - 1)
by A32, A36, XREAL_1:64;
then
(pp - qq) . k <= H1(
k)
by A10, A35;
hence
(pp - qq) . k <= p2 . k
by A19, A23, A34;
verum
end;
A37:
p2 is Element of (len p) -tuples_on REAL
by A18, FINSEQ_2:92;
hence
Sum pp <= Sum qq
by A8, A33, A22, A31, RVSUM_1:82, XREAL_1:50; ( ( ( for k being Nat st k in dom p holds
p . k = q . k ) implies Sum pp = Sum qq ) & ( Sum pp = Sum qq implies for k being Nat st k in dom p holds
p . k = q . k ) & ( ex k being Nat st
( k in dom p & p . k <> q . k ) implies Sum pp < Sum qq ) & ( Sum pp < Sum qq implies ex k being Nat st
( k in dom p & p . k <> q . k ) ) )
A38:
( ex k being Nat st
( k in Seg (len p) & p . k <> q . k ) implies Sum pp < Sum qq )
proof
assume
ex
k being
Nat st
(
k in Seg (len p) &
p . k <> q . k )
;
Sum pp < Sum qq
then consider k1 being
Nat such that A39:
k1 in Seg (len p)
and A40:
p . k1 <> q . k1
;
A41:
k1 in dom p
by A39, FINSEQ_1:def 3;
then A42:
p . k1 > 0
by A4;
then A43:
(p . k1) * (log (2,number_e)) > 0
by A32, XREAL_1:129;
q . k1 > 0
by A4, A41;
then A44:
(q . k1) / (p . k1) > 0
by A42, XREAL_1:139;
(q . k1) / (p . k1) <> 1
by A40, XCMPLX_1:58;
then
log (
number_e,
((q . k1) / (p . k1)))
< ((q . k1) / (p . k1)) - 1
by A44, Th3;
then
((p . k1) * (log (2,number_e))) * (log (number_e,((q . k1) / (p . k1)))) < ((p . k1) * (log (2,number_e))) * (((q . k1) / (p . k1)) - 1)
by A43, XREAL_1:68;
then
(pp - qq) . k1 < H1(
k1)
by A10, A41;
then
(pp - qq) . k1 < p2 . k1
by A19, A23, A39;
then
(Sum pp) - (Sum qq) < 0
by A8, A33, A22, A37, A31, A39, RVSUM_1:83;
hence
Sum pp < Sum qq
by XREAL_1:48;
verum
end;
A45:
dom (pp - qq) = dom p2
by A21, A18, FINSEQ_3:29;
thus
( ( for k being Nat st k in dom p holds
p . k = q . k ) iff Sum pp = Sum qq )
( ex k being Nat st
( k in dom p & p . k <> q . k ) iff Sum pp < Sum qq )proof
hereby ( Sum pp = Sum qq implies for k being Nat st k in dom p holds
p . k = q . k )
assume A46:
for
k being
Nat st
k in dom p holds
p . k = q . k
;
Sum pp = Sum qq
for
k being
Nat st
k in dom p holds
(pp - qq) . k = p2 . k
proof
let k be
Nat;
( k in dom p implies (pp - qq) . k = p2 . k )
assume A47:
k in dom p
;
(pp - qq) . k = p2 . k
A48:
p . k = q . k
by A46, A47;
p . k > 0
by A4, A47;
then
(q . k) / (p . k) = 1
by A48, XCMPLX_1:60;
then
((p . k) * (log (2,number_e))) * (log (number_e,((q . k) / (p . k)))) = ((p . k) * (log (2,number_e))) * (((q . k) / (p . k)) - 1)
by Th3;
then A49:
(pp - qq) . k = H1(
k)
by A10, A47;
k in Seg (len p)
by A47, FINSEQ_1:def 3;
hence
(pp - qq) . k = p2 . k
by A19, A23, A49;
verum
end; then
Sum (pp - qq) = 0
by A20, A45, A31, FINSEQ_1:13;
hence
Sum pp = Sum qq
by A8;
verum
end;
assume A50:
Sum pp = Sum qq
;
for k being Nat st k in dom p holds
p . k = q . k
assume
ex
k being
Nat st
(
k in dom p & not
p . k = q . k )
;
contradiction
hence
contradiction
by A26, A38, A50;
verum
end;
hence
( ex k being Nat st
( k in dom p & p . k <> q . k ) iff Sum pp < Sum qq )
by A26, A38; verum