let p be Prime; for a, b being Element of (GF p)
for F1, F2 being set st p > 3 & Disc (a,b,p) <> 0. (GF p) & F1 = {(Class ((R_EllCur (a,b,p)),[0,1,0]))} & F2 = { (Class ((R_EllCur (a,b,p)),P)) where P is Element of ProjCo (GF p) : ( P in EC_SetProjCo (a,b,p) & ex X, Y being Element of (GF p) st P = [X,Y,1] ) } holds
F1 misses F2
let a, b be Element of (GF p); for F1, F2 being set st p > 3 & Disc (a,b,p) <> 0. (GF p) & F1 = {(Class ((R_EllCur (a,b,p)),[0,1,0]))} & F2 = { (Class ((R_EllCur (a,b,p)),P)) where P is Element of ProjCo (GF p) : ( P in EC_SetProjCo (a,b,p) & ex X, Y being Element of (GF p) st P = [X,Y,1] ) } holds
F1 misses F2
let F1, F2 be set ; ( p > 3 & Disc (a,b,p) <> 0. (GF p) & F1 = {(Class ((R_EllCur (a,b,p)),[0,1,0]))} & F2 = { (Class ((R_EllCur (a,b,p)),P)) where P is Element of ProjCo (GF p) : ( P in EC_SetProjCo (a,b,p) & ex X, Y being Element of (GF p) st P = [X,Y,1] ) } implies F1 misses F2 )
assume A1:
( p > 3 & Disc (a,b,p) <> 0. (GF p) & F1 = {(Class ((R_EllCur (a,b,p)),[0,1,0]))} & F2 = { (Class ((R_EllCur (a,b,p)),P)) where P is Element of ProjCo (GF p) : ( P in EC_SetProjCo (a,b,p) & ex X, Y being Element of (GF p) st P = [X,Y,1] ) } )
; F1 misses F2
assume
F1 meets F2
; contradiction
then
F1 /\ F2 <> {}
by XBOOLE_0:def 7;
then consider z being object such that
A2:
z in F1 /\ F2
by XBOOLE_0:def 1;
A3:
( z in F1 & z in F2 )
by A2, XBOOLE_0:def 4;
consider P being Element of ProjCo (GF p) such that
A4:
( z = Class ((R_EllCur (a,b,p)),P) & P in EC_SetProjCo (a,b,p) & ex X, Y being Element of (GF p) st P = [X,Y,1] )
by A1, A3;
consider X1, Y1 being Element of (GF p) such that
A5:
P = [X1,Y1,1]
by A4;
A6:
z = Class ((R_EllCur (a,b,p)),[0,1,0])
by A1, A3, TARSKI:def 1;
reconsider Q = [0,1,0] as Element of ProjCo (GF p) by Lm5;
A7:
Q is Element of EC_SetProjCo (a,b,p)
by Th42;
Q in Class ((R_EllCur (a,b,p)),P)
by A4, A6, EQREL_1:23;
then
[P,Q] in R_EllCur (a,b,p)
by EQREL_1:18;
then
P _EQ_ Q
by Th47, A1, A7, A4;
then consider a being Element of (GF p) such that
A8:
( a <> 0. (GF p) & Q `1_3 = a * (P `1_3) & Q `2_3 = a * (P `2_3) & Q `3_3 = a * (P `3_3) )
by Def10;
A9:
p > 1
by INT_2:def 4;
A10: 1. (GF p) =
1
by A9, INT_3:14
.=
P `3_3
by A5
;
0. (GF p) =
0
by Th11
.=
a * (P `3_3)
by A8
.=
a
by A10
;
hence
contradiction
by A8; verum