let p be prime odd Nat; for m being positive Nat holds
( len (x. (m,p)) = m & len (ff_0 (m,p)) = m + 1 & (ff_0 (m,p)) . ((len (x. (m,p))) + 1) = (tau 0) |^ (p -' 1) )
let m be positive Nat; ( len (x. (m,p)) = m & len (ff_0 (m,p)) = m + 1 & (ff_0 (m,p)) . ((len (x. (m,p))) + 1) = (tau 0) |^ (p -' 1) )
A1:
len <*((tau 0) |^ (p -' 1))*> = 1
by FINSEQ_1:40;
len (ff_0 (m,p)) =
(len (x. (m,p))) + (len <*((tau 0) |^ (p -' 1))*>)
by FINSEQ_1:22
.=
m + 1
by Def2, A1
;
hence
( len (x. (m,p)) = m & len (ff_0 (m,p)) = m + 1 & (ff_0 (m,p)) . ((len (x. (m,p))) + 1) = (tau 0) |^ (p -' 1) )
by Def2; verum