let n be Nat; for h, x being Real
for f being Function of REAL,REAL holds ((fdif (f,h)) . (n + 1)) . x = (((fdif (f,h)) . n) . (x + h)) - (((fdif (f,h)) . n) . x)
let h, x be Real; for f being Function of REAL,REAL holds ((fdif (f,h)) . (n + 1)) . x = (((fdif (f,h)) . n) . (x + h)) - (((fdif (f,h)) . n) . x)
let f be Function of REAL,REAL; ((fdif (f,h)) . (n + 1)) . x = (((fdif (f,h)) . n) . (x + h)) - (((fdif (f,h)) . n) . x)
defpred S1[ Nat] means ((fdif (f,h)) . ($1 + 1)) . x = (((fdif (f,h)) . $1) . (x + h)) - (((fdif (f,h)) . $1) . x);
A1:
for i being Nat st S1[i] holds
S1[i + 1]
proof
let i be
Nat;
( S1[i] implies S1[i + 1] )
assume
((fdif (f,h)) . (i + 1)) . x = (((fdif (f,h)) . i) . (x + h)) - (((fdif (f,h)) . i) . x)
;
S1[i + 1]
A2:
(fdif (f,h)) . (i + 1) is
Function of
REAL,
REAL
by DIFF_1:2;
((fdif (f,h)) . (i + 2)) . x =
((fdif (f,h)) . ((i + 1) + 1)) . x
.=
(fD (((fdif (f,h)) . (i + 1)),h)) . x
by DIFF_1:def 6
.=
(((fdif (f,h)) . (i + 1)) . (x + h)) - (((fdif (f,h)) . (i + 1)) . x)
by A2, DIFF_1:3
;
hence
S1[
i + 1]
;
verum
end;
A3:
S1[ 0 ]
by Th40;
for n being Nat holds S1[n]
from NAT_1:sch 2(A3, A1);
hence
((fdif (f,h)) . (n + 1)) . x = (((fdif (f,h)) . n) . (x + h)) - (((fdif (f,h)) . n) . x)
; verum