let n be Nat; for h, x being Real
for f being Function of REAL,REAL holds ((fdif (f,h)) . n) . x = ((bdif (f,h)) . n) . (x + (n * h))
let h, x be Real; for f being Function of REAL,REAL holds ((fdif (f,h)) . n) . x = ((bdif (f,h)) . n) . (x + (n * h))
let f be Function of REAL,REAL; ((fdif (f,h)) . n) . x = ((bdif (f,h)) . n) . (x + (n * h))
defpred S1[ Nat] means for x being Real holds ((fdif (f,h)) . $1) . x = ((bdif (f,h)) . $1) . (x + ($1 * h));
A1:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A2:
for
x being
Real holds
((fdif (f,h)) . k) . x = ((bdif (f,h)) . k) . (x + (k * h))
;
S1[k + 1]
let x be
Real;
((fdif (f,h)) . (k + 1)) . x = ((bdif (f,h)) . (k + 1)) . (x + ((k + 1) * h))
A3:
((fdif (f,h)) . k) . (x + h) = ((bdif (f,h)) . k) . ((x + h) + (k * h))
by A2;
A4:
(fdif (f,h)) . k is
Function of
REAL,
REAL
by Th2;
A5:
(bdif (f,h)) . k is
Function of
REAL,
REAL
by Th12;
((fdif (f,h)) . (k + 1)) . x =
(fD (((fdif (f,h)) . k),h)) . x
by Def6
.=
(((fdif (f,h)) . k) . (x + h)) - (((fdif (f,h)) . k) . x)
by A4, Th3
.=
(((bdif (f,h)) . k) . ((x + h) + (k * h))) - (((bdif (f,h)) . k) . (x + (k * h)))
by A2, A3
.=
(((bdif (f,h)) . k) . (x + ((k + 1) * h))) - (((bdif (f,h)) . k) . ((x + ((k + 1) * h)) - h))
.=
(bD (((bdif (f,h)) . k),h)) . (x + ((k + 1) * h))
by A5, Th4
.=
((bdif (f,h)) . (k + 1)) . (x + ((k + 1) * h))
by Def7
;
hence
((fdif (f,h)) . (k + 1)) . x = ((bdif (f,h)) . (k + 1)) . (x + ((k + 1) * h))
;
verum
end;
A6:
S1[ 0 ]
for n being Nat holds S1[n]
from NAT_1:sch 2(A6, A1);
hence
((fdif (f,h)) . n) . x = ((bdif (f,h)) . n) . (x + (n * h))
; verum