let seq1, seq2 be without-infty ExtREAL_sequence; ( seq1 is convergent_to_-infty & seq2 is convergent_to_finite_number implies ( seq1 + seq2 is convergent_to_-infty & seq1 + seq2 is convergent & lim (seq1 + seq2) = -infty ) )
assume A1:
( seq1 is convergent_to_-infty & seq2 is convergent_to_finite_number )
; ( seq1 + seq2 is convergent_to_-infty & seq1 + seq2 is convergent & lim (seq1 + seq2) = -infty )
then consider S2 being Real such that
A2:
for g being Real st 0 < g holds
ex n being Nat st
for m being Nat st n <= m holds
|.((seq2 . m) - S2).| < g
by MESFUNC5:def 8;
now for g being Real st g < 0 holds
ex n being Nat st
for m being Nat st n <= m holds
(seq1 + seq2) . m <= glet g be
Real;
( g < 0 implies ex n being Nat st
for m being Nat st n <= m holds
(seq1 + seq2) . m <= g )assume A3:
g < 0
;
ex n being Nat st
for m being Nat st n <= m holds
(seq1 + seq2) . m <= gset G =
min (
(- 1),
((2 * g) - S2));
A4:
(
min (
(- 1),
((2 * g) - S2))
<= - 1 &
min (
(- 1),
((2 * g) - S2))
<= (2 * g) - S2 )
by XXREAL_0:17;
then consider n1 being
Nat such that A5:
for
m being
Nat st
n1 <= m holds
seq1 . m <= min (
(- 1),
((2 * g) - S2))
by A1, MESFUNC5:def 10;
consider n2 being
Nat such that A6:
for
m being
Nat st
n2 <= m holds
|.((seq2 . m) - S2).| < - g
by A2, A3;
reconsider N1 =
n1,
N2 =
n2 as
Element of
NAT by ORDINAL1:def 12;
reconsider n =
max (
N1,
N2) as
Nat ;
A7:
(
n1 <= n &
n2 <= n )
by XXREAL_0:25;
now for m being Nat st n <= m holds
(seq1 + seq2) . m <= glet m be
Nat;
( n <= m implies (seq1 + seq2) . m <= g )assume
n <= m
;
(seq1 + seq2) . m <= gthen
(
n1 <= m &
n2 <= m )
by A7, XXREAL_0:2;
then A8:
(
seq1 . m <= min (
(- 1),
((2 * g) - S2)) &
|.((seq2 . m) - S2).| < - g )
by A5, A6;
reconsider g1 =
g as
R_eal by XXREAL_0:def 1;
B1:
- g1 = - g
by XXREAL_3:def 3;
then
(seq2 . m) - S2 < - g1
by A8, EXTREAL1:21;
then
seq2 . m < (- g1) + S2
by XXREAL_3:54;
then A9:
(seq1 . m) + (seq2 . m) <= (min ((- 1),((2 * g) - S2))) + ((- g1) + S2)
by A8, XXREAL_3:36;
(- g1) + S2 = (- g) + S2
by B1, XXREAL_3:def 2;
then
((2 * g) - S2) + ((- g1) + S2) = ((2 * g) - S2) + ((- g) + S2)
by XXREAL_3:def 2;
then
(min ((- 1),((2 * g) - S2))) + ((- g1) + S2) <= g
by A4, XXREAL_3:36;
then A10:
(seq1 . m) + (seq2 . m) <= g
by A9, XXREAL_0:2;
m is
Element of
NAT
by ORDINAL1:def 12;
hence
(seq1 + seq2) . m <= g
by A10, Th7;
verum end; hence
ex
n being
Nat st
for
m being
Nat st
n <= m holds
(seq1 + seq2) . m <= g
;
verum end;
hence A11:
seq1 + seq2 is convergent_to_-infty
by MESFUNC5:def 10; ( seq1 + seq2 is convergent & lim (seq1 + seq2) = -infty )
hence
seq1 + seq2 is convergent
; lim (seq1 + seq2) = -infty
thus
lim (seq1 + seq2) = -infty
by A11, MESFUNC5:def 12; verum