let seq1, seq2 be without+infty ExtREAL_sequence; ( seq1 is convergent_to_+infty & seq2 is convergent_to_finite_number implies ( seq1 + seq2 is convergent_to_+infty & seq1 + seq2 is convergent & lim (seq1 + seq2) = +infty ) )
assume A1:
( seq1 is convergent_to_+infty & seq2 is convergent_to_finite_number )
; ( seq1 + seq2 is convergent_to_+infty & seq1 + seq2 is convergent & lim (seq1 + seq2) = +infty )
then consider S2 being Real such that
A2:
for g being Real st 0 < g holds
ex n being Nat st
for m being Nat st n <= m holds
|.((seq2 . m) - S2).| < g
by MESFUNC5:def 8;
now for g being Real st 0 < g holds
ex n being Nat st
for m being Nat st n <= m holds
g <= (seq1 + seq2) . mlet g be
Real;
( 0 < g implies ex n being Nat st
for m being Nat st n <= m holds
g <= (seq1 + seq2) . m )assume A3:
0 < g
;
ex n being Nat st
for m being Nat st n <= m holds
g <= (seq1 + seq2) . mset G =
max (1,
((2 * g) - S2));
A4:
( 1
<= max (1,
((2 * g) - S2)) &
(2 * g) - S2 <= max (1,
((2 * g) - S2)) )
by XXREAL_0:25;
then consider n1 being
Nat such that A5:
for
m being
Nat st
n1 <= m holds
max (1,
((2 * g) - S2))
<= seq1 . m
by A1, MESFUNC5:def 9;
consider n2 being
Nat such that A6:
for
m being
Nat st
n2 <= m holds
|.((seq2 . m) - S2).| < g
by A2, A3;
reconsider N1 =
n1,
N2 =
n2 as
Element of
NAT by ORDINAL1:def 12;
reconsider n =
max (
N1,
N2) as
Nat ;
A7:
(
n1 <= n &
n2 <= n )
by XXREAL_0:25;
now for m being Nat st n <= m holds
g <= (seq1 + seq2) . mlet m be
Nat;
( n <= m implies g <= (seq1 + seq2) . m )assume
n <= m
;
g <= (seq1 + seq2) . mthen
(
n1 <= m &
n2 <= m )
by A7, XXREAL_0:2;
then A8:
(
max (1,
((2 * g) - S2))
<= seq1 . m &
|.((seq2 . m) - S2).| < g )
by A5, A6;
reconsider g1 =
g as
R_eal by XXREAL_0:def 1;
- g1 < (seq2 . m) - S2
by A8, EXTREAL1:21;
then
(- g1) + S2 < seq2 . m
by XXREAL_3:53;
then A9:
(max (1,((2 * g) - S2))) + ((- g1) + S2) <= (seq1 . m) + (seq2 . m)
by A8, XXREAL_3:36;
- g1 = - g
by XXREAL_3:def 3;
then
(- g1) + S2 = (- g) + S2
by XXREAL_3:def 2;
then
((2 * g) - S2) + ((- g1) + S2) = ((2 * g) - S2) + ((- g) + S2)
by XXREAL_3:def 2;
then
g <= (max (1,((2 * g) - S2))) + ((- g1) + S2)
by A4, XXREAL_3:36;
then A10:
g <= (seq1 . m) + (seq2 . m)
by A9, XXREAL_0:2;
m is
Element of
NAT
by ORDINAL1:def 12;
hence
g <= (seq1 + seq2) . m
by A10, Th7;
verum end; hence
ex
n being
Nat st
for
m being
Nat st
n <= m holds
g <= (seq1 + seq2) . m
;
verum end;
hence A11:
seq1 + seq2 is convergent_to_+infty
by MESFUNC5:def 9; ( seq1 + seq2 is convergent & lim (seq1 + seq2) = +infty )
hence
seq1 + seq2 is convergent
; lim (seq1 + seq2) = +infty
thus
lim (seq1 + seq2) = +infty
by A11, MESFUNC5:def 12; verum