then reconsider m = M as Nat ;
m + 1 = M + 1
; then A2:
( m + 1 inNAT & N <= m + 1 )
byA1; then
N inNATbyTh5; then reconsider n = N as Nat ;
( n <= m or n = m + 1 )
byA2, NAT_1:8; then
( N <= M or N = m + 1 )
; hence
( N <= M or N = M + 1 )
; :: thesis: verum