let GX be TopSpace; ( GX is connected iff for A, B being Subset of GX st [#] GX = A \/ B & A <> {} GX & B <> {} GX & A is closed & B is closed holds
A meets B )
A1:
now ( not GX is connected implies ex A, B being Subset of GX st
( [#] GX = A \/ B & A <> {} GX & B <> {} GX & A is closed & B is closed & A misses B ) )assume
not
GX is
connected
;
ex A, B being Subset of GX st
( [#] GX = A \/ B & A <> {} GX & B <> {} GX & A is closed & B is closed & A misses B )then consider P,
Q being
Subset of
GX such that A2:
[#] GX = P \/ Q
and A3:
P,
Q are_separated
and A4:
P <> {} GX
and A5:
Q <> {} GX
;
A6:
Q is
closed
by A2, A3, Th4;
P is
closed
by A2, A3, Th4;
hence
ex
A,
B being
Subset of
GX st
(
[#] GX = A \/ B &
A <> {} GX &
B <> {} GX &
A is
closed &
B is
closed &
A misses B )
by A2, A3, A4, A5, A6, Th1;
verum end;
( ex A, B being Subset of GX st
( [#] GX = A \/ B & A <> {} GX & B <> {} GX & A is closed & B is closed & A misses B ) implies not GX is connected )
by Th2;
hence
( GX is connected iff for A, B being Subset of GX st [#] GX = A \/ B & A <> {} GX & B <> {} GX & A is closed & B is closed holds
A meets B )
by A1; verum