let X be AffinPlane; ( X is Desarguesian implies X is satisfying_major_Scherungssatz )
assume A1:
X is Desarguesian
; X is satisfying_major_Scherungssatz
now for o, a1, a2, a3, a4, b1, b2, b3, b4 being Element of X
for M, N being Subset of X st M is being_line & N is being_line & o in M & o in N & a1 in M & a3 in M & b1 in M & b3 in M & a2 in N & a4 in N & b2 in N & b4 in N & not a4 in M & not a2 in M & not b2 in M & not b4 in M & not a1 in N & not a3 in N & not b1 in N & not b3 in N & a3,a2 // b3,b2 & a2,a1 // b2,b1 & a1,a4 // b1,b4 holds
a3,a4 // b3,b4let o,
a1,
a2,
a3,
a4,
b1,
b2,
b3,
b4 be
Element of
X;
for M, N being Subset of X st M is being_line & N is being_line & o in M & o in N & a1 in M & a3 in M & b1 in M & b3 in M & a2 in N & a4 in N & b2 in N & b4 in N & not a4 in M & not a2 in M & not b2 in M & not b4 in M & not a1 in N & not a3 in N & not b1 in N & not b3 in N & a3,a2 // b3,b2 & a2,a1 // b2,b1 & a1,a4 // b1,b4 holds
a3,a4 // b3,b4let M,
N be
Subset of
X;
( M is being_line & N is being_line & o in M & o in N & a1 in M & a3 in M & b1 in M & b3 in M & a2 in N & a4 in N & b2 in N & b4 in N & not a4 in M & not a2 in M & not b2 in M & not b4 in M & not a1 in N & not a3 in N & not b1 in N & not b3 in N & a3,a2 // b3,b2 & a2,a1 // b2,b1 & a1,a4 // b1,b4 implies a3,a4 // b3,b4 )assume that A2:
M is
being_line
and A3:
N is
being_line
and A4:
o in M
and A5:
o in N
and A6:
a1 in M
and A7:
a3 in M
and A8:
b1 in M
and A9:
b3 in M
and A10:
a2 in N
and A11:
a4 in N
and A12:
b2 in N
and A13:
b4 in N
and A14:
not
a4 in M
and A15:
not
a2 in M
and A16:
not
b2 in M
and
not
b4 in M
and A17:
not
a1 in N
and A18:
not
a3 in N
and A19:
not
b1 in N
and
not
b3 in N
and A20:
a3,
a2 // b3,
b2
and A21:
a2,
a1 // b2,
b1
and A22:
a1,
a4 // b1,
b4
;
a3,a4 // b3,b4A23:
now ( a1 <> a3 & a2 <> a4 implies a3,a4 // b3,b4 )A24:
now ( ex x, y, z being Element of X st
( LIN x,y,z & x <> y & x <> z & y <> z ) implies a3,a4 // b3,b4 )assume
ex
x,
y,
z being
Element of
X st
(
LIN x,
y,
z &
x <> y &
x <> z &
y <> z )
;
a3,a4 // b3,b4then consider d being
Element of
X such that A25:
LIN a1,
a2,
d
and A26:
a1 <> d
and A27:
a2 <> d
by TRANSLAC:1;
LIN o,
d,
d
by AFF_1:7;
then consider Y being
Subset of
X such that A28:
Y is
being_line
and A29:
o in Y
and A30:
d in Y
and
d in Y
by AFF_1:21;
a1,
a2 // a1,
d
by A25, AFF_1:def 1;
then
a2,
a1 // a1,
d
by AFF_1:4;
then A31:
b2,
b1 // a1,
d
by A6, A15, A21, AFF_1:5;
A32:
(
N <> M &
N <> Y &
M <> Y )
proof
A33:
now ( not N = Y & not M = Y )A34:
LIN a1,
d,
a2
by A25, AFF_1:6;
assume A35:
(
N = Y or
M = Y )
;
contradiction
LIN a2,
d,
a1
by A25, AFF_1:6;
hence
contradiction
by A2, A3, A6, A10, A15, A17, A26, A27, A30, A35, A34, AFF_1:25;
verum end;
assume
( not
N <> M or not
N <> Y or not
M <> Y )
;
contradiction
hence
contradiction
by A11, A14, A33;
verum
end; A36:
ex
d1 being
Element of
X st
(
LIN b1,
b2,
d1 &
d1 in Y )
proof
not
b1,
b2 // o,
d
proof
A37:
o <> d
assume
b1,
b2 // o,
d
;
contradiction
then
b2,
b1 // o,
d
by AFF_1:4;
then A38:
a2,
a1 // o,
d
by A8, A16, A21, AFF_1:5;
a1,
a2 // a1,
d
by A25, AFF_1:def 1;
then
a2,
a1 // a1,
d
by AFF_1:4;
then
a1,
d // o,
d
by A6, A15, A38, AFF_1:5;
then
d,
o // d,
a1
by AFF_1:4;
then
LIN d,
o,
a1
by AFF_1:def 1;
then
LIN o,
d,
a1
by AFF_1:6;
then
o,
d // o,
a1
by AFF_1:def 1;
then A39:
Y // M
by A2, A4, A5, A6, A17, A28, A29, A30, A37, AFF_1:38;
LIN a2,
a1,
d
by A25, AFF_1:6;
then
a2,
a1 // a2,
d
by AFF_1:def 1;
then
a2,
d // o,
d
by A6, A15, A38, AFF_1:5;
then
d,
a2 // d,
o
by AFF_1:4;
then
LIN d,
a2,
o
by AFF_1:def 1;
then
LIN o,
d,
a2
by AFF_1:6;
then
o,
d // o,
a2
by AFF_1:def 1;
then
Y // N
by A3, A4, A5, A10, A15, A28, A29, A30, A37, AFF_1:38;
then
M // N
by A39, AFF_1:44;
hence
contradiction
by A4, A5, A11, A14, AFF_1:45;
verum
end;
then consider d1 being
Element of
X such that A40:
LIN b1,
b2,
d1
and A41:
LIN o,
d,
d1
by AFF_1:60;
take
d1
;
( LIN b1,b2,d1 & d1 in Y )
o <> d
hence
(
LIN b1,
b2,
d1 &
d1 in Y )
by A28, A29, A30, A40, A41, AFF_1:25;
verum
end;
LIN a2,
a1,
d
by A25, AFF_1:6;
then
a2,
a1 // a2,
d
by AFF_1:def 1;
then A42:
b2,
b1 // a2,
d
by A6, A15, A21, AFF_1:5;
A43:
o <> d
consider d1 being
Element of
X such that A44:
LIN b1,
b2,
d1
and A45:
d1 in Y
by A36;
b1,
b2 // b1,
d1
by A44, AFF_1:def 1;
then
b2,
b1 // b1,
d1
by AFF_1:4;
then
a1,
d // b1,
d1
by A8, A16, A31, AFF_1:5;
then A46:
d,
a4 // d1,
b4
by A1, A2, A3, A4, A5, A6, A8, A11, A13, A14, A17, A22, A28, A29, A30, A45, A43, A32, AFF_2:def 4;
LIN b2,
b1,
d1
by A44, AFF_1:6;
then
b2,
b1 // b2,
d1
by AFF_1:def 1;
then A47:
a2,
d // b2,
d1
by A8, A16, A42, AFF_1:5;
a2,
a3 // b2,
b3
by A20, AFF_1:4;
then
d,
a3 // d1,
b3
by A1, A2, A3, A4, A5, A7, A9, A10, A12, A15, A18, A28, A29, A30, A45, A43, A32, A47, AFF_2:def 4;
hence
a3,
a4 // b3,
b4
by A1, A2, A3, A4, A5, A7, A9, A11, A13, A14, A18, A28, A29, A30, A45, A43, A32, A46, AFF_2:def 4;
verum end; assume that A48:
a1 <> a3
and A49:
a2 <> a4
;
a3,a4 // b3,b4now ( ( for x, y, z being Element of X holds
( not LIN x,y,z or not x <> y or not x <> z or not y <> z ) ) implies a3,a4 // b3,b4 )assume A50:
for
x,
y,
z being
Element of
X holds
( not
LIN x,
y,
z or not
x <> y or not
x <> z or not
y <> z )
;
a3,a4 // b3,b4A51:
now ( a1 = b1 implies a3,a4 // b3,b4 )assume A52:
a1 = b1
;
a3,a4 // b3,b4A53:
a2 <> b4
proof
assume
a2 = b4
;
contradiction
then
LIN a1,
a4,
a2
by A22, A52, AFF_1:def 1;
then
LIN a2,
a4,
a1
by AFF_1:6;
hence
contradiction
by A3, A10, A11, A17, A49, AFF_1:25;
verum
end; A54:
a1 <> b3
proof
assume
a1 = b3
;
contradiction
then
b2,
b1 // a2,
a3
by A20, A52, AFF_1:4;
then A55:
a2,
a1 // a2,
a3
by A8, A16, A21, AFF_1:5;
LIN o,
a1,
a3
by A2, A4, A6, A7, AFF_1:21;
hence
contradiction
by A3, A4, A5, A10, A15, A17, A48, A55, AFF_1:14, AFF_1:25;
verum
end;
LIN a2,
a4,
b4
by A3, A10, A11, A13, AFF_1:21;
then A56:
(
a2 = b4 or
a4 = b4 )
by A49, A50;
LIN a1,
a3,
b3
by A2, A6, A7, A9, AFF_1:21;
then
a3 = b3
by A48, A50, A54;
hence
a3,
a4 // b3,
b4
by A56, A53, AFF_1:2;
verum end; A57:
now ( a3 = b1 implies a3,a4 // b3,b4 )assume A58:
a3 = b1
;
a3,a4 // b3,b4A59:
a2 <> b2
proof
assume
a2 = b2
;
contradiction
then
LIN a2,
a1,
a3
by A21, A58, AFF_1:def 1;
then
LIN a1,
a3,
a2
by AFF_1:6;
hence
contradiction
by A2, A6, A7, A15, A48, AFF_1:25;
verum
end; A60:
a3 <> b3
proof
assume
a3 = b3
;
contradiction
then
a3,
a2 // b2,
b1
by A20, A58, AFF_1:4;
then
a3,
a2 // a2,
a1
by A8, A16, A21, AFF_1:5;
then
a2,
a3 // a2,
a1
by AFF_1:4;
then
LIN a2,
a3,
a1
by AFF_1:def 1;
then
LIN a1,
a3,
a2
by AFF_1:6;
hence
contradiction
by A2, A6, A7, A15, A48, AFF_1:25;
verum
end; A61:
a4 <> b4
proof
assume
a4 = b4
;
contradiction
then
a4,
a1 // a4,
a3
by A22, A58, AFF_1:4;
then
LIN a4,
a1,
a3
by AFF_1:def 1;
then
LIN a1,
a3,
a4
by AFF_1:6;
hence
contradiction
by A2, A6, A7, A14, A48, AFF_1:25;
verum
end;
LIN a2,
a4,
b4
by A3, A10, A11, A13, AFF_1:21;
then A62:
a2 = b4
by A49, A50, A61;
LIN a2,
a4,
b2
by A3, A10, A11, A12, AFF_1:21;
then
a4 = b2
by A49, A50, A59;
then A63:
a3,
a4 // b2,
b1
by A58, AFF_1:2;
LIN a1,
a3,
b3
by A2, A6, A7, A9, AFF_1:21;
then
a1 = b3
by A48, A50, A60;
then
a3,
a4 // b4,
b3
by A8, A16, A21, A62, A63, AFF_1:5;
hence
a3,
a4 // b3,
b4
by AFF_1:4;
verum end;
LIN a1,
a3,
b1
by A2, A6, A7, A8, AFF_1:21;
hence
a3,
a4 // b3,
b4
by A48, A50, A51, A57;
verum end; hence
a3,
a4 // b3,
b4
by A24;
verum end; now ( ( a1 = a3 or a2 = a4 ) implies a3,a4 // b3,b4 )A64:
now ( a2 = a4 implies a3,a4 // b3,b4 )
o,
b2 // o,
b4
by A3, A5, A12, A13, AFF_1:39, AFF_1:41;
then A65:
LIN o,
b2,
b4
by AFF_1:def 1;
assume A66:
a2 = a4
;
a3,a4 // b3,b4
a1,
a2 // b1,
b2
by A21, AFF_1:4;
then
b1,
b2 // b1,
b4
by A6, A14, A22, A66, AFF_1:5;
hence
a3,
a4 // b3,
b4
by A2, A4, A5, A8, A16, A19, A20, A66, A65, AFF_1:14, AFF_1:25;
verum end; A67:
now ( a1 = a3 implies a3,a4 // b3,b4 )
o,
b1 // o,
b3
by A2, A4, A8, A9, AFF_1:39, AFF_1:41;
then A68:
LIN o,
b1,
b3
by AFF_1:def 1;
assume A69:
a1 = a3
;
a3,a4 // b3,b4then
a2,
a1 // b2,
b3
by A20, AFF_1:4;
then
b2,
b1 // b2,
b3
by A6, A15, A21, AFF_1:5;
hence
a3,
a4 // b3,
b4
by A3, A4, A5, A12, A16, A19, A22, A69, A68, AFF_1:14, AFF_1:25;
verum end; assume
(
a1 = a3 or
a2 = a4 )
;
a3,a4 // b3,b4hence
a3,
a4 // b3,
b4
by A67, A64;
verum end; hence
a3,
a4 // b3,
b4
by A23;
verum end;
hence
X is satisfying_major_Scherungssatz
; verum