let n be Element of NAT ; the_Complex_Space n is regular
let p be Point of (the_Complex_Space n); COMPTS_1:def 2 for b1 being Element of K10( the carrier of (the_Complex_Space n)) holds
( b1 = {} or not b1 is closed or not p in b1 ` or ex b2, b3 being Element of K10( the carrier of (the_Complex_Space n)) st
( b2 is open & b3 is open & p in b2 & b1 c= b3 & b2 misses b3 ) )
let P be Subset of (the_Complex_Space n); ( P = {} or not P is closed or not p in P ` or ex b1, b2 being Element of K10( the carrier of (the_Complex_Space n)) st
( b1 is open & b2 is open & p in b1 & P c= b2 & b1 misses b2 ) )
assume that
A1:
P <> {}
and
A2:
( P is closed & p in P ` )
; ex b1, b2 being Element of K10( the carrier of (the_Complex_Space n)) st
( b1 is open & b2 is open & p in b1 & P c= b2 & b1 misses b2 )
reconsider A = P as Subset of (COMPLEX n) ;
reconsider z1 = p as Element of COMPLEX n ;
set d = (dist (z1,A)) / 2;
reconsider K1 = Ball (z1,((dist (z1,A)) / 2)), K2 = Ball (A,((dist (z1,A)) / 2)) as Subset of (the_Complex_Space n) ;
take
K1
; ex b1 being Element of K10( the carrier of (the_Complex_Space n)) st
( K1 is open & b1 is open & p in K1 & P c= b1 & K1 misses b1 )
take
K2
; ( K1 is open & K2 is open & p in K1 & P c= K2 & K1 misses K2 )
A3:
Ball (z1,((dist (z1,A)) / 2)) is open
by SEQ_4:112;
Ball (A,((dist (z1,A)) / 2)) is open
by A1, SEQ_4:122;
hence
( K1 is open & K2 is open )
by A3; ( p in K1 & P c= K2 & K1 misses K2 )
( A is closed & not p in P )
by A2, Th5, XBOOLE_0:def 5;
then
0 < (dist (z1,A)) / 2
by A1, SEQ_4:117, XREAL_1:215;
hence
( p in K1 & P c= K2 )
by SEQ_4:111, SEQ_4:121; K1 misses K2
assume
K1 /\ K2 <> {}
; XBOOLE_0:def 7 contradiction
then consider x being Element of COMPLEX n such that
A4:
x in (Ball (z1,((dist (z1,A)) / 2))) /\ (Ball (A,((dist (z1,A)) / 2)))
by SUBSET_1:4;
x in K2
by A4, XBOOLE_0:def 4;
then A5:
dist (x,A) < (dist (z1,A)) / 2
by SEQ_4:119;
x in K1
by A4, XBOOLE_0:def 4;
then
|.(z1 - x).| < (dist (z1,A)) / 2
by SEQ_4:110;
then
|.(z1 - x).| + (dist (x,A)) < ((dist (z1,A)) / 2) + ((dist (z1,A)) / 2)
by A5, XREAL_1:8;
hence
contradiction
by A1, SEQ_4:118; verum