let a, b, c, d be positive Real; ( max (a,b) = max (c,d) & min (a,b) = min (c,d) iff ( a * b = c * d & a + b = c + d ) )
A1:
( a + b = (max (a,b)) + (min (a,b)) & c + d = (max (c,d)) + (min (c,d)) & a * b = (max (a,b)) * (min (a,b)) & (max (c,d)) * (min (c,d)) = c * d )
by NEWTON04:18;
( a * b = c * d & a + b = c + d implies ( max (a,b) = max (c,d) & min (a,b) = min (c,d) ) )
proof
assume B1:
(
a * b = c * d &
a + b = c + d )
;
( max (a,b) = max (c,d) & min (a,b) = min (c,d) )
then
max (
a,
b)
= max (
c,
d)
by ISM;
hence
(
max (
a,
b)
= max (
c,
d) &
min (
a,
b)
= min (
c,
d) )
by A1, B1;
verum
end;
hence
( max (a,b) = max (c,d) & min (a,b) = min (c,d) iff ( a * b = c * d & a + b = c + d ) )
by A1; verum