let T be non empty T_1 TopSpace; ( ( for A being Subset of T st A is infinite & A is countable holds
not Der A is empty ) implies T is countably_compact )
assume A1:
for A being Subset of T st A is infinite & A is countable holds
not Der A is empty
; T is countably_compact
assume
not T is countably_compact
; contradiction
then consider S being non-empty closed SetSequence of T such that
A2:
S is non-ascending
and
A3:
meet S = {}
by Th22;
defpred S1[ object , object ] means $2 in S . $1;
A4:
for x being object st x in NAT holds
ex y being object st
( y in the carrier of T & S1[x,y] )
consider F being sequence of T such that
A6:
for x being object st x in NAT holds
S1[x,F . x]
from FUNCT_2:sch 1(A4);
reconsider rngF = rng F as Subset of T ;
A7:
for n being Nat holds F . n in S . n
by A6, ORDINAL1:def 12;
dom F = NAT
by FUNCT_2:def 1;
then
rng F is countable
by CARD_3:93;
then
not Der rngF is empty
by A1, A2, A3, A7, Th24;
then consider p being object such that
A8:
p in Der rngF
by XBOOLE_0:def 1;
reconsider p = p as Point of T by A8;
consider n being Nat such that
A9:
not p in S . n
by A3, KURATO_0:3;
A10:
p in (S . n) `
by A9, XBOOLE_0:def 5;
deffunc H1( set ) -> set = F . $1;
set F1n = { H1(i) where i is Element of NAT : i in n + 1 } ;
A11:
{ H1(i) where i is Element of NAT : i in n + 1 } c= the carrier of T
A12:
n + 1 is finite
;
A13:
{ H1(i) where i is Element of NAT : i in n + 1 } is finite
from FRAENKEL:sch 21(A12);
reconsider F1n = { H1(i) where i is Element of NAT : i in n + 1 } as Subset of T by A11;
set U = ((S . n) `) \ (F1n \ {p});
reconsider U = ((S . n) `) \ (F1n \ {p}) as Subset of T ;
p in {p}
by TARSKI:def 1;
then
not p in F1n \ {p}
by XBOOLE_0:def 5;
then A14:
p in U
by A10, XBOOLE_0:def 5;
S . n is closed
by Def6;
then
U is open
by A13, FRECHET:4;
then consider q being Point of T such that
A15:
q in rngF /\ U
and
A16:
q <> p
by A8, A14, TOPGEN_1:17;
q in rngF
by A15, XBOOLE_0:def 4;
then consider i being object such that
A17:
i in dom F
and
A18:
F . i = q
by FUNCT_1:def 3;
reconsider i = i as Element of NAT by A17;