let X1, X2 be set ; ( ( for x being object holds
( x in X1 iff ex y, z being object st
( x = [y,z] & [{y},z] in Trace f ) ) ) & ( for x being object holds
( x in X2 iff ex y, z being object st
( x = [y,z] & [{y},z] in Trace f ) ) ) implies X1 = X2 )
assume A1:
( ( for x being object holds
( x in X1 iff ex y, z being object st
( x = [y,z] & [{y},z] in Trace f ) ) ) & ( for x being object holds
( x in X2 iff ex y, z being object st
( x = [y,z] & [{y},z] in Trace f ) ) ) & not X1 = X2 )
; contradiction
then consider x being object such that
A2:
( ( x in X1 & not x in X2 ) or ( x in X2 & not x in X1 ) )
by TARSKI:2;
( x in X2 iff for y, z being object holds
( not x = [y,z] or not [{y},z] in Trace f ) )
by A1, A2;
hence
contradiction
by A1; verum