let s be Real; :: thesis: ( 0< s implies ex k being Nat st for m, n being Nat st k <= m & k <= n holds ||.((seq . m)-(seq . n)).||< s ) assume 0< s
; :: thesis: ex k being Nat st for m, n being Nat st k <= m & k <= n holds ||.((seq . m)-(seq . n)).||< s then consider k being Nat such that A3:
for m being Nat st k <= m holds ||.((seq . m)-(seq . k)).||< s / 2
byA2;