let X be non empty set ; ( {{}} is Element of X implies not {{}} in Funcs X )
assume A1:
{{}} is Element of X
; not {{}} in Funcs X
assume A2:
{{}} in Funcs X
; contradiction
set FAB = { (Funcs (A,B)) where A, B is Element of X : verum } ;
reconsider x = {{}} as Element of X by A1;
consider y being set such that
A3:
( x in y & y in { (Funcs (A,B)) where A, B is Element of X : verum } )
by A2, TARSKI:def 4;
consider A, B being Element of X such that
A4:
y = Funcs (A,B)
by A3;
consider f being Function such that
A5:
x = f
and
A6:
dom f = A
and
A7:
rng f c= B
by A3, A4, FUNCT_2:def 2;
reconsider f = f as Function of A,B by A6, A7, FUNCT_2:2;
A8:
{{}} = f
by A5;
{} in {{}}
by TARSKI:def 1;
then consider u, v being object such that
u in A
and
v in B
and
A9:
{} = [u,v]
by A8, ZFMISC_1:def 2;
thus
contradiction
by A9; verum