let i be Nat; :: thesis: ex x being set st x in (sequence_univers . (i + 1)) \ (sequence_univers . i)
assume for x being set holds not x in (sequence_univers . (i + 1)) \ (sequence_univers . i) ; :: thesis: contradiction
then A1: (sequence_univers . (i + 1)) \ (sequence_univers . i) is empty ;
then A2: sequence_univers . (i + 1) = sequence_univers . i by Th105, XBOOLE_1:37;
per cases ( i = 0 or i <> 0 ) ;
end;