A5:
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set
for n being Nat holds F5(S,A,x,n) is non-empty MSAlgebra over F4(S,x,n)
by A3;
defpred S3[ object , object , Nat] means ex S being non empty non void strict unsplit gate`1=arity gate`2isBoolean ManySortedSign ex A being strict gate`2=den Boolean Circuit of S st
( S = $1 & A = $2 );
consider f, g, h being ManySortedSet of NAT such that
A6:
( f . 0 = F1() & g . 0 = F3() & h . 0 = F6() )
and
A7:
for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) )
from CIRCCMB2:sch 12();
A8:
for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n & S2[S,A,x,n] holds
S2[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]
;
A9:
ex S being non empty ManySortedSign ex A being non-empty MSAlgebra over S ex x being set st
( S = f . 0 & A = g . 0 & x = h . 0 & S2[S,A,x, 0 ] )
by A6;
A10:
for n being Nat ex S being non empty ManySortedSign ex A being non-empty MSAlgebra over S st
( S = f . n & A = g . n & S2[S,A,h . n,n] )
from CIRCCMB2:sch 13(A9, A7, A8, A5);
defpred S4[ object , object , object , Nat] means S3[$1,$2,$4];
A11:
for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n & S4[S,A,x,n] holds
S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]
proof
let n be
Nat;
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n & S4[S,A,x,n] holds
S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]let S be non
empty ManySortedSign ;
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n & S4[S,A,x,n] holds
S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]let A be
non-empty MSAlgebra over
S;
for x being set st S = f . n & A = g . n & x = h . n & S4[S,A,x,n] holds
S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]let x be
set ;
( S = f . n & A = g . n & x = h . n & S4[S,A,x,n] implies S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1] )
assume that
S = f . n
and
A = g . n
and
x = h . n
and A12:
S3[
S,
A,
n]
;
S4[F4(S,x,n),F5(S,A,x,n),F7(x,n),n + 1]
reconsider S =
S as non
empty non
void strict unsplit gate`1=arity gate`2isBoolean ManySortedSign by A12;
reconsider A =
A as
strict gate`2=den Boolean Circuit of
S by A12;
reconsider S1 =
F4(
S,
x,
n) as non
empty non
void strict unsplit gate`1=arity gate`2isBoolean ManySortedSign by A1;
F5(
S,
A,
x,
n) is
strict gate`2=den Boolean Circuit of
S1
by A4;
hence
S4[
F4(
S,
x,
n),
F5(
S,
A,
x,
n),
F7(
x,
n),
n + 1]
;
verum
end;
A13:
ex S being non empty ManySortedSign ex A being non-empty MSAlgebra over S ex x being set st
( S = f . 0 & A = g . 0 & x = h . 0 & S4[S,A,x, 0 ] )
by A6;
for n being Nat ex S being non empty ManySortedSign ex A being non-empty MSAlgebra over S st
( S = f . n & A = g . n & S4[S,A,h . n,n] )
from CIRCCMB2:sch 13(A13, A7, A11, A5);
then consider S being non empty ManySortedSign , A being non-empty MSAlgebra over S such that
A14:
S = f . F8()
and
A15:
A = g . F8()
and
A16:
S3[S,A,F8()]
;
consider f1, h1 being ManySortedSet of NAT such that
A17:
F2() = f1 . F8()
and
A18:
f1 . 0 = F1()
and
A19:
h1 . 0 = F6()
and
A20:
for n being Nat
for S being non empty ManySortedSign
for x being set st S = f1 . n & x = h1 . n holds
( f1 . (n + 1) = F4(S,x,n) & h1 . (n + 1) = F7(x,n) )
by A2;
A21:
for n being Nat
for S being non empty ManySortedSign
for x being set st S = f1 . n & x = h1 . n & S1[S,x,n] holds
S1[F4(S,x,n),F7(x,n),n + 1]
;
defpred S5[ Nat] means h1 . $1 = h . $1;
A22:
ex S being non empty ManySortedSign ex x being set st
( S = f1 . 0 & x = h1 . 0 & S1[S,x, 0 ] )
by A18;
A23:
for n being Nat ex S being non empty ManySortedSign st
( S = f1 . n & S1[S,h1 . n,n] )
from CIRCCMB2:sch 2(A22, A20, A21);
A24:
now for n being Nat st S5[n] holds
S5[n + 1]end;
A27:
S5[ 0 ]
by A6, A19;
A28:
for i being Nat holds S5[i]
from NAT_1:sch 2(A27, A24);
defpred S6[ Nat] means f1 . $1 = f . $1;
for i being object st i in NAT holds
h1 . i = h . i
by A28;
then A29:
h1 = h
by PBOOLE:3;
A30:
now for n being Nat st S6[n] holds
S6[n + 1]end;
A33:
S6[ 0 ]
by A6, A18;
A34:
for i being Nat holds S6[i]
from NAT_1:sch 2(A33, A30);
then
for i being object st i in NAT holds
f1 . i = f . i
;
then
f1 = f
by PBOOLE:3;
then reconsider A = A as strict gate`2=den Boolean Circuit of F2() by A17, A14, A16;
take
A
; ex f, g, h being ManySortedSet of NAT st
( F2() = f . F8() & A = g . F8() & f . 0 = F1() & g . 0 = F3() & h . 0 = F6() & ( for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) ) ) )
take
f
; ex g, h being ManySortedSet of NAT st
( F2() = f . F8() & A = g . F8() & f . 0 = F1() & g . 0 = F3() & h . 0 = F6() & ( for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) ) ) )
take
g
; ex h being ManySortedSet of NAT st
( F2() = f . F8() & A = g . F8() & f . 0 = F1() & g . 0 = F3() & h . 0 = F6() & ( for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) ) ) )
take
h
; ( F2() = f . F8() & A = g . F8() & f . 0 = F1() & g . 0 = F3() & h . 0 = F6() & ( for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) ) ) )
thus
( F2() = f . F8() & A = g . F8() & f . 0 = F1() & g . 0 = F3() & h . 0 = F6() & ( for n being Nat
for S being non empty ManySortedSign
for A being non-empty MSAlgebra over S
for x being set st S = f . n & A = g . n & x = h . n holds
( f . (n + 1) = F4(S,x,n) & g . (n + 1) = F5(S,A,x,n) & h . (n + 1) = F7(x,n) ) ) )
by A6, A7, A17, A34, A15; verum