let d be non zero Nat; for G being Grating of d
for A being Subset of (REAL d) holds
( A in cells (0,G) iff ex x being Element of REAL d st
( A = cell (x,x) & ( for i being Element of Seg d holds x . i in G . i ) ) )
let G be Grating of d; for A being Subset of (REAL d) holds
( A in cells (0,G) iff ex x being Element of REAL d st
( A = cell (x,x) & ( for i being Element of Seg d holds x . i in G . i ) ) )
let A be Subset of (REAL d); ( A in cells (0,G) iff ex x being Element of REAL d st
( A = cell (x,x) & ( for i being Element of Seg d holds x . i in G . i ) ) )
hereby ( ex x being Element of REAL d st
( A = cell (x,x) & ( for i being Element of Seg d holds x . i in G . i ) ) implies A in cells (0,G) )
assume
A in cells (
0,
G)
;
ex x being Element of REAL d st
( A = cell (x,x) & ( for i being Element of Seg d holds x . i in G . i ) )then consider l,
r being
Element of
REAL d such that A1:
A = cell (
l,
r)
and A2:
( ex
X being
Subset of
(Seg d) st
(
card X = 0 & ( for
i being
Element of
Seg d holds
( (
i in X &
l . i < r . i &
[(l . i),(r . i)] is
Gap of
G . i ) or ( not
i in X &
l . i = r . i &
l . i in G . i ) ) ) ) or (
0 = d & ( for
i being
Element of
Seg d holds
(
r . i < l . i &
[(l . i),(r . i)] is
Gap of
G . i ) ) ) )
by Th29;
consider X being
Subset of
(Seg d) such that A3:
card X = 0
and A4:
for
i being
Element of
Seg d holds
( (
i in X &
l . i < r . i &
[(l . i),(r . i)] is
Gap of
G . i ) or ( not
i in X &
l . i = r . i &
l . i in G . i ) )
by A2;
reconsider l9 =
l,
r9 =
r as
Function of
(Seg d),
REAL by Def3;
X = {}
by A3;
then A5:
for
i being
Element of
Seg d holds
(
l9 . i = r9 . i &
l . i in G . i )
by A4;
then
l9 = r9
by FUNCT_2:63;
hence
ex
x being
Element of
REAL d st
(
A = cell (
x,
x) & ( for
i being
Element of
Seg d holds
x . i in G . i ) )
by A1, A5;
verum
end;
given x being Element of REAL d such that A6:
A = cell (x,x)
and
A7:
for i being Element of Seg d holds x . i in G . i
; A in cells (0,G)
ex X being Subset of (Seg d) st
( card X = 0 & ( for i being Element of Seg d holds
( ( i in X & x . i < x . i & [(x . i),(x . i)] is Gap of G . i ) or ( not i in X & x . i = x . i & x . i in G . i ) ) ) )
hence
A in cells (0,G)
by A6, Th29; verum