let f1, f2 be PartFunc of COMPLEX,COMPLEX; for Z being open Subset of COMPLEX st Z c= dom (f1 + f2) & f1 is_differentiable_on Z & f2 is_differentiable_on Z holds
( f1 + f2 is_differentiable_on Z & ( for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x)) ) )
let Z be open Subset of COMPLEX; ( Z c= dom (f1 + f2) & f1 is_differentiable_on Z & f2 is_differentiable_on Z implies ( f1 + f2 is_differentiable_on Z & ( for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x)) ) ) )
assume that
A1:
Z c= dom (f1 + f2)
and
A2:
( f1 is_differentiable_on Z & f2 is_differentiable_on Z )
; ( f1 + f2 is_differentiable_on Z & ( for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x)) ) )
hence A3:
f1 + f2 is_differentiable_on Z
by A1, Th15; for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x))
now for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x))let x be
Complex;
( x in Z implies ((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x)) )assume A4:
x in Z
;
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x))then A5:
(
f1 is_differentiable_in x &
f2 is_differentiable_in x )
by A2, Th15;
thus ((f1 + f2) `| Z) /. x =
diff (
(f1 + f2),
x)
by A3, A4, Def12
.=
(diff (f1,x)) + (diff (f2,x))
by A5, Th23
;
verum end;
hence
for x being Complex st x in Z holds
((f1 + f2) `| Z) /. x = (diff (f1,x)) + (diff (f2,x))
; verum