let n be Nat; ( n > 1 implies ((((2 * n) -' 2) !) * n) * (n + 1) < (2 * n) ! )
assume A1:
n > 1
; ((((2 * n) -' 2) !) * n) * (n + 1) < (2 * n) !
then A2:
2 * 1 < 2 * n
by XREAL_1:68;
then A3:
((2 * n) -' 1) + 1 = 2 * n
by XREAL_1:235, XXREAL_0:2;
2 - 1 < (2 * n) - 1
by A2, XREAL_1:9;
then A4:
1 < (2 * n) -' 1
by A2, XREAL_1:233, XXREAL_0:2;
((2 * n) -' 2) + 1 =
(((2 * n) -' 1) -' 1) + 1
by NAT_D:45
.=
(2 * n) -' 1
by A4, XREAL_1:235
;
then A5: ((((2 * n) -' 2) !) * ((2 * n) -' 1)) * (2 * n) =
(((2 * n) -' 1) !) * (2 * n)
by NEWTON:15
.=
(2 * n) !
by A3, NEWTON:15
;
((2 * n) -' 2) ! > 0
by NEWTON:17;
then A6:
( (((2 * n) -' 2) !) * n > 0 * n & (((2 * n) -' 2) !) * n < (((2 * n) -' 2) !) * ((2 * n) -' 1) )
by A1, Th3, XREAL_1:68;
n + 1 < n + n
by A1, XREAL_1:6;
hence
((((2 * n) -' 2) !) * n) * (n + 1) < (2 * n) !
by A5, A6, XREAL_1:98; verum