let C be CategoryStr ; ( C is associative iff C opp is associative )
hereby ( C opp is associative implies C is associative )
assume A1:
C is
associative
;
C opp is associative
for
g1,
g2,
g3 being
morphism of
(C opp) st
g1 |> g2 &
g2 |> g3 &
g1 (*) g2 |> g3 &
g1 |> g2 (*) g3 holds
g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3
proof
let g1,
g2,
g3 be
morphism of
(C opp);
( g1 |> g2 & g2 |> g3 & g1 (*) g2 |> g3 & g1 |> g2 (*) g3 implies g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3 )
reconsider f3 =
g1,
f2 =
g2,
f1 =
g3 as
morphism of
C ;
assume
g1 |> g2
;
( not g2 |> g3 or not g1 (*) g2 |> g3 or not g1 |> g2 (*) g3 or g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3 )
then A2:
f2 |> f3
by FUNCT_4:42;
assume
g2 |> g3
;
( not g1 (*) g2 |> g3 or not g1 |> g2 (*) g3 or g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3 )
then A3:
f1 |> f2
by FUNCT_4:42;
assume A4:
g1 (*) g2 |> g3
;
( not g1 |> g2 (*) g3 or g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3 )
assume A5:
g1 |> g2 (*) g3
;
g1 (*) (g2 (*) g3) = (g1 (*) g2) (*) g3
A6:
g1 (*) g2 = f2 (*) f3
by A2, Th3;
then A7:
f1 |> f2 (*) f3
by A4, FUNCT_4:42;
A8:
f1 (*) f2 = g2 (*) g3
by A3, Th3;
then A9:
f1 (*) f2 |> f3
by A5, FUNCT_4:42;
thus g1 (*) (g2 (*) g3) =
(f1 (*) f2) (*) f3
by A8, A9, Th3
.=
f1 (*) (f2 (*) f3)
by A1, A2, A3, A7, A9
.=
(g1 (*) g2) (*) g3
by A6, A7, Th3
;
verum
end; hence
C opp is
associative
;
verum
end;
assume A10:
C opp is associative
; C is associative
for f1, f2, f3 being morphism of C st f1 |> f2 & f2 |> f3 & f1 (*) f2 |> f3 & f1 |> f2 (*) f3 holds
f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3
proof
let f1,
f2,
f3 be
morphism of
C;
( f1 |> f2 & f2 |> f3 & f1 (*) f2 |> f3 & f1 |> f2 (*) f3 implies f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3 )
reconsider g3 =
f1,
g2 =
f2,
g1 =
f3 as
morphism of
(C opp) ;
assume A11:
f1 |> f2
;
( not f2 |> f3 or not f1 (*) f2 |> f3 or not f1 |> f2 (*) f3 or f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3 )
then A12:
g2 |> g3
by FUNCT_4:42;
assume A13:
f2 |> f3
;
( not f1 (*) f2 |> f3 or not f1 |> f2 (*) f3 or f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3 )
then A14:
g1 |> g2
by FUNCT_4:42;
assume A15:
f1 (*) f2 |> f3
;
( not f1 |> f2 (*) f3 or f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3 )
assume A16:
f1 |> f2 (*) f3
;
f1 (*) (f2 (*) f3) = (f1 (*) f2) (*) f3
A17:
f1 (*) f2 = g2 (*) g3
by A11, Th3;
then A18:
g1 |> g2 (*) g3
by A15, FUNCT_4:42;
A19:
g1 (*) g2 = f2 (*) f3
by A13, Th3;
then A20:
g1 (*) g2 |> g3
by A16, FUNCT_4:42;
thus f1 (*) (f2 (*) f3) =
(g1 (*) g2) (*) g3
by A19, A16, Th3
.=
g1 (*) (g2 (*) g3)
by A10, A12, A14, A18, A20
.=
(f1 (*) f2) (*) f3
by A17, A15, Th3
;
verum
end;
hence
C is associative
; verum