let F1, F2 be set ; ( ( for x being set holds
( x in F1 iff x is Functor of C,D ) ) & ( for x being set holds
( x in F2 iff x is Functor of C,D ) ) implies F1 = F2 )
assume that
A3:
for x being set holds
( x in F1 iff x is Functor of C,D )
and
A4:
for x being set holds
( x in F2 iff x is Functor of C,D )
; F1 = F2
hence
F1 = F2
by TARSKI:2; verum