let s be finite set ; for t being non empty finite set st card s = 23 & card t = 365 holds
2 * (card (not-one-to-one (s,t))) > card (Funcs (s,t))
let t be non empty finite set ; ( card s = 23 & card t = 365 implies 2 * (card (not-one-to-one (s,t))) > card (Funcs (s,t)) )
assume A1:
card s = 23
; ( not card t = 365 or 2 * (card (not-one-to-one (s,t))) > card (Funcs (s,t)) )
assume A2:
card t = 365
; 2 * (card (not-one-to-one (s,t))) > card (Funcs (s,t))
then
card (not-one-to-one (s,t)) = (365 |^ 23) - ((365 !) / ((365 -' 23) !))
by Th16, A1;
hence
2 * (card (not-one-to-one (s,t))) > card (Funcs (s,t))
by Lm1, A1, A2, CARD_FIN:4; verum