let y, X9 be set ; for F, Ch being Function st y in rng Ch & Ch " {y} c= X9 holds
Intersection ((F | X9),Ch,y) = Intersection (F,Ch,y)
let F, Ch be Function; ( y in rng Ch & Ch " {y} c= X9 implies Intersection ((F | X9),Ch,y) = Intersection (F,Ch,y) )
assume that
A1:
y in rng Ch
and
A2:
Ch " {y} c= X9
; Intersection ((F | X9),Ch,y) = Intersection (F,Ch,y)
A3:
Intersection (F,Ch,y) c= Intersection ((F | X9),Ch,y)
proof
let z be
object ;
TARSKI:def 3 ( not z in Intersection (F,Ch,y) or z in Intersection ((F | X9),Ch,y) )
assume A4:
z in Intersection (
F,
Ch,
y)
;
z in Intersection ((F | X9),Ch,y)
A5:
now for x being set st x in dom Ch & Ch . x = y holds
z in (F | X9) . xlet x be
set ;
( x in dom Ch & Ch . x = y implies z in (F | X9) . x )assume that A6:
x in dom Ch
and A7:
Ch . x = y
;
z in (F | X9) . x
Ch . x in {y}
by A7, TARSKI:def 1;
then A8:
x in Ch " {y}
by A6, FUNCT_1:def 7;
z in F . x
by A4, A6, A7, Def2;
then
x in dom F
by FUNCT_1:def 2;
then
x in (dom F) /\ X9
by A2, A8, XBOOLE_0:def 4;
then A9:
x in dom (F | X9)
by RELAT_1:61;
z in F . x
by A4, A6, A7, Def2;
hence
z in (F | X9) . x
by A9, FUNCT_1:47;
verum end;
consider x being
set such that A10:
x in dom Ch
and A11:
Ch . x = y
and A12:
z in F . x
by A1, A4, Th21;
Ch . x in {y}
by A11, TARSKI:def 1;
then A13:
x in Ch " {y}
by A10, FUNCT_1:def 7;
x in dom F
by A12, FUNCT_1:def 2;
then
x in (dom F) /\ X9
by A2, A13, XBOOLE_0:def 4;
then
x in dom (F | X9)
by RELAT_1:61;
then A14:
(F | X9) . x in rng (F | X9)
by FUNCT_1:def 3;
z in (F | X9) . x
by A5, A10, A11;
then
z in union (rng (F | X9))
by A14, TARSKI:def 4;
hence
z in Intersection (
(F | X9),
Ch,
y)
by A5, Def2;
verum
end;
Intersection ((F | X9),Ch,y) c= Intersection (F,Ch,y)
by Th28;
hence
Intersection ((F | X9),Ch,y) = Intersection (F,Ch,y)
by A3; verum