let X be finite set ; for k being Nat
for x1, x2 being object st card X < k holds
Choose (X,k,x1,x2) is empty
let k be Nat; for x1, x2 being object st card X < k holds
Choose (X,k,x1,x2) is empty
let x1, x2 be object ; ( card X < k implies Choose (X,k,x1,x2) is empty )
assume A1:
card X < k
; Choose (X,k,x1,x2) is empty
assume
not Choose (X,k,x1,x2) is empty
; contradiction
then consider z being object such that
A2:
z in Choose (X,k,x1,x2)
;
ex f being Function of X,{x1,x2} st
( f = z & card (f " {x1}) = k )
by A2, Def1;
hence
contradiction
by A1, NAT_1:43; verum