let x be object ; for f, g being Function holds pi ({f,g},x) = {(f . x),(g . x)}
let f, g be Function; pi ({f,g},x) = {(f . x),(g . x)}
thus
pi ({f,g},x) c= {(f . x),(g . x)}
XBOOLE_0:def 10 {(f . x),(g . x)} c= pi ({f,g},x)proof
let y be
object ;
TARSKI:def 3 ( not y in pi ({f,g},x) or y in {(f . x),(g . x)} )
assume
y in pi (
{f,g},
x)
;
y in {(f . x),(g . x)}
then consider f1 being
Function such that A1:
f1 in {f,g}
and A2:
y = f1 . x
by Def6;
(
f1 = f or
f1 = g )
by A1, TARSKI:def 2;
hence
y in {(f . x),(g . x)}
by A2, TARSKI:def 2;
verum
end;
let y be object ; TARSKI:def 3 ( not y in {(f . x),(g . x)} or y in pi ({f,g},x) )
assume A3:
y in {(f . x),(g . x)}
; y in pi ({f,g},x)
A4:
f in {f,g}
by TARSKI:def 2;
A5:
g in {f,g}
by TARSKI:def 2;
( y = g . x or y = f . x )
by A3, TARSKI:def 2;
hence
y in pi ({f,g},x)
by A4, A5, Def6; verum