let x be object ; :: thesis: for f, g being Function holds pi ({f,g},x) = {(f . x),(g . x)}
let f, g be Function; :: thesis: pi ({f,g},x) = {(f . x),(g . x)}
thus pi ({f,g},x) c= {(f . x),(g . x)} :: according to XBOOLE_0:def 10 :: thesis: {(f . x),(g . x)} c= pi ({f,g},x)
proof
let y be object ; :: according to TARSKI:def 3 :: thesis: ( not y in pi ({f,g},x) or y in {(f . x),(g . x)} )
assume y in pi ({f,g},x) ; :: thesis: y in {(f . x),(g . x)}
then consider f1 being Function such that
A1: f1 in {f,g} and
A2: y = f1 . x by Def6;
( f1 = f or f1 = g ) by A1, TARSKI:def 2;
hence y in {(f . x),(g . x)} by A2, TARSKI:def 2; :: thesis: verum
end;
let y be object ; :: according to TARSKI:def 3 :: thesis: ( not y in {(f . x),(g . x)} or y in pi ({f,g},x) )
assume A3: y in {(f . x),(g . x)} ; :: thesis: y in pi ({f,g},x)
A4: f in {f,g} by TARSKI:def 2;
A5: g in {f,g} by TARSKI:def 2;
( y = g . x or y = f . x ) by A3, TARSKI:def 2;
hence y in pi ({f,g},x) by A4, A5, Def6; :: thesis: verum