let K, L, M, N be Cardinal; ( K in L & M in N implies ( K +` M in L +` N & M +` K in L +` N ) )
A1:
for K, L, M, N being Cardinal st K in L & M in N & L c= N holds
K +` M in L +` N
proof
let K,
L,
M,
N be
Cardinal;
( K in L & M in N & L c= N implies K +` M in L +` N )
assume that A2:
K in L
and A3:
M in N
and A4:
L c= N
;
K +` M in L +` N
per cases
( N is finite or not N is finite )
;
suppose A5:
N is
finite
;
K +` M in L +` Nthen reconsider N =
N as
finite Cardinal ;
reconsider L =
L,
M =
M,
K =
K as
finite Cardinal by A2, A3, A4, A5, CARD_3:92;
A6:
card (Segm K) = K
;
A7:
card (Segm L) = L
;
A8:
card (Segm M) = M
;
A9:
card (Segm N) = N
;
A10:
K +` M = card (Segm ((card K) + (card M)))
by Th37;
A11:
L +` N = card (Segm ((card L) + (card N)))
by Th37;
A12:
card K < card L
by A2, A6, A7, NAT_1:41;
card M < card N
by A3, A8, A9, NAT_1:41;
then
(card K) + (card M) < (card L) + (card N)
by A12, XREAL_1:8;
hence
K +` M in L +` N
by A10, A11, NAT_1:41;
verum end; suppose A13:
not
N is
finite
;
K +` M in L +` Nthen A14:
L +` N = N
by A4, Th75;
A15:
omega c= N
by A13, CARD_3:85;
( (
K c= M & (
M is
finite or not
M is
finite ) ) or (
M c= K & (
K is
finite or not
K is
finite ) ) )
;
then A16:
( (
K is
finite &
M is
finite ) or
K +` M = M or (
K +` M = K &
K in N ) )
by A2, A4, Th75;
(
K is
finite &
M is
finite implies
K +` M in L +` N )
by A14, A15, CARD_1:61;
hence
K +` M in L +` N
by A3, A4, A13, A16, Th75;
verum end; end;
end;
( L c= N or N c= L )
;
hence
( K in L & M in N implies ( K +` M in L +` N & M +` K in L +` N ) )
by A1; verum