let K, M, N be Cardinal; exp ((K *` M),N) = (exp (K,N)) *` (exp (M,N))
( card (K *` M) = K *` M & card N = card N )
;
hence exp ((K *` M),N) =
card (Funcs (N,[:K,M:]))
by FUNCT_5:61
.=
card [:(Funcs (N,K)),(Funcs (N,M)):]
by FUNCT_5:64
.=
(exp (K,N)) *` (exp (M,N))
by Th6
;
verum