let Y be non empty set ; for G being Subset of (PARTITIONS Y)
for A, B, C being a_partition of Y st G = {A,B,C} & A <> B & C <> A holds
CompF (A,G) = B '/\' C
let G be Subset of (PARTITIONS Y); for A, B, C being a_partition of Y st G = {A,B,C} & A <> B & C <> A holds
CompF (A,G) = B '/\' C
let A, B, C be a_partition of Y; ( G = {A,B,C} & A <> B & C <> A implies CompF (A,G) = B '/\' C )
assume that
A1:
G = {A,B,C}
and
A2:
A <> B
and
A3:
C <> A
; CompF (A,G) = B '/\' C
per cases
( B = C or B <> C )
;
suppose A5:
B <> C
;
CompF (A,G) = B '/\' CA6:
G \ {A} =
({A} \/ {B,C}) \ {A}
by A1, ENUMSET1:2
.=
({A} \ {A}) \/ ({B,C} \ {A})
by XBOOLE_1:42
;
( not
B in {A} & not
C in {A} )
by A2, A3, TARSKI:def 1;
then A7:
G \ {A} =
({A} \ {A}) \/ {B,C}
by A6, ZFMISC_1:63
.=
{} \/ {B,C}
by XBOOLE_1:37
.=
{B,C}
;
A8:
'/\' (G \ {A}) c= B '/\' C
proof
let x be
object ;
TARSKI:def 3 ( not x in '/\' (G \ {A}) or x in B '/\' C )
reconsider xx =
x as
set by TARSKI:1;
assume
x in '/\' (G \ {A})
;
x in B '/\' C
then consider h being
Function,
F being
Subset-Family of
Y such that A9:
dom h = G \ {A}
and A10:
rng h = F
and A11:
for
d being
set st
d in G \ {A} holds
h . d in d
and A12:
x = Intersect F
and A13:
x <> {}
by BVFUNC_2:def 1;
A14:
not
x in {{}}
by A13, TARSKI:def 1;
B in dom h
by A7, A9, TARSKI:def 2;
then A15:
h . B in rng h
by FUNCT_1:def 3;
A16:
(h . B) /\ (h . C) c= xx
C in G \ {A}
by A7, TARSKI:def 2;
then A22:
h . C in C
by A11;
B in G \ {A}
by A7, TARSKI:def 2;
then A23:
h . B in B
by A11;
C in dom h
by A7, A9, TARSKI:def 2;
then A24:
h . C in rng h
by FUNCT_1:def 3;
xx c= (h . B) /\ (h . C)
then
(h . B) /\ (h . C) = x
by A16, XBOOLE_0:def 10;
then
x in INTERSECTION (
B,
C)
by A23, A22, SETFAM_1:def 5;
then
x in (INTERSECTION (B,C)) \ {{}}
by A14, XBOOLE_0:def 5;
hence
x in B '/\' C
by PARTIT1:def 4;
verum
end; A25:
B '/\' C c= '/\' (G \ {A})
proof
let x be
object ;
TARSKI:def 3 ( not x in B '/\' C or x in '/\' (G \ {A}) )
reconsider xx =
x as
set by TARSKI:1;
assume A26:
x in B '/\' C
;
x in '/\' (G \ {A})
then A27:
x <> {}
by EQREL_1:def 4;
x in (INTERSECTION (B,C)) \ {{}}
by A26, PARTIT1:def 4;
then consider a,
b being
set such that A28:
a in B
and A29:
b in C
and A30:
x = a /\ b
by SETFAM_1:def 5;
set h0 = (
B,
C)
--> (
a,
b);
A31:
dom ((B,C) --> (a,b)) = G \ {A}
by A7, FUNCT_4:62;
A32:
rng ((B,C) --> (a,b)) = {a,b}
by A5, FUNCT_4:64;
rng ((B,C) --> (a,b)) c= bool Y
then reconsider F =
rng ((B,C) --> (a,b)) as
Subset-Family of
Y ;
A34:
xx c= Intersect F
A37:
for
d being
set st
d in G \ {A} holds
((B,C) --> (a,b)) . d in d
proof
let d be
set ;
( d in G \ {A} implies ((B,C) --> (a,b)) . d in d )
assume A38:
d in G \ {A}
;
((B,C) --> (a,b)) . d in d
now ( ( d = B & ((B,C) --> (a,b)) . d in d ) or ( d = C & ((B,C) --> (a,b)) . d in d ) )end;
hence
((B,C) --> (a,b)) . d in d
;
verum
end;
Intersect F c= xx
then
x = Intersect F
by A34, XBOOLE_0:def 10;
hence
x in '/\' (G \ {A})
by A31, A37, A27, BVFUNC_2:def 1;
verum
end;
CompF (
A,
G)
= '/\' (G \ {A})
by BVFUNC_2:def 7;
hence
CompF (
A,
G)
= B '/\' C
by A25, A8, XBOOLE_0:def 10;
verum end; end;