let P be Element of (ProjectiveSpace (TOP-REAL 3)); for u being non zero Element of (TOP-REAL 3) st P = Dir u & P in BK_model holds
u . 3 <> 0
let u be non zero Element of (TOP-REAL 3); ( P = Dir u & P in BK_model implies u . 3 <> 0 )
assume that
A1:
P = Dir u
and
A2:
P in BK_model
; u . 3 <> 0
assume A3:
u . 3 = 0
; contradiction
consider Q being Point of (ProjectiveSpace (TOP-REAL 3)) such that
A4:
P = Q
and
A5:
for u being Element of (TOP-REAL 3) st not u is zero & Q = Dir u holds
qfconic (1,1,(- 1),0,0,0,u) is negative
by A2;
A6:
qfconic (1,1,(- 1),0,0,0,u) is negative
by A1, A4, A5;
qfconic (1,1,(- 1),0,0,0,u) =
((((((1 * (u . 1)) * (u . 1)) + ((1 * (u . 2)) * (u . 2))) + (((- 1) * (u . 3)) * (u . 3))) + ((0 * (u . 1)) * (u . 2))) + ((0 * (u . 1)) * (u . 3))) + ((0 * (u . 2)) * (u . 3))
by PASCAL:def 1
.=
((u . 1) ^2) + ((u . 2) ^2)
by A3
;
then
( u . 1 = 0 & u . 2 = 0 )
by A6, BKMODEL1:19;
then
( u `1 = 0 & u `2 = 0 & u `3 = 0 )
by A3, EUCLID_5:def 1, EUCLID_5:def 2, EUCLID_5:def 3;
hence
contradiction
by EUCLID_5:3, EUCLID_5:4; verum