let D be non empty set ; for A being Matrix of 1,3,D holds A = <*<*(A * (1,1)),(A * (1,2)),(A * (1,3))*>*>
let A be Matrix of 1,3,D; A = <*<*(A * (1,1)),(A * (1,2)),(A * (1,3))*>*>
reconsider B = <*<*(A * (1,1)),(A * (1,2)),(A * (1,3))*>*> as Matrix of 1,3,D by Th24;
A1:
( len A = 1 & width A = 3 )
by MATRIX_0:23;
A2:
for i, j being Nat st [i,j] in Indices A holds
A * (i,j) = B * (i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices A implies A * (i,j) = B * (i,j) )
A3:
Indices B = [:(Seg 1),(Seg 3):]
by MATRIX_0:23;
A4:
Indices A = [:(Seg 1),(Seg 3):]
by MATRIX_0:23;
assume A5:
[i,j] in Indices A
;
A * (i,j) = B * (i,j)
then
i in {1}
by A4, ZFMISC_1:87, FINSEQ_1:2;
then A6:
i = 1
by TARSKI:def 1;
j in {1,2,3}
by A4, A5, ZFMISC_1:87, FINSEQ_3:1;
end;
( len B = 1 & width B = 3 )
by MATRIX_0:23;
hence
A = <*<*(A * (1,1)),(A * (1,2)),(A * (1,3))*>*>
by A1, A2, MATRIX_0:21; verum