let T0, T1 be Tree; for t being Element of tree (T0,T1) holds
( ( for p being Element of T0 st t = <*0*> ^ p holds
( t in Leaves (tree (T0,T1)) iff p in Leaves T0 ) ) & ( for p being Element of T1 st t = <*1*> ^ p holds
( t in Leaves (tree (T0,T1)) iff p in Leaves T1 ) ) )
let t be Element of tree (T0,T1); ( ( for p being Element of T0 st t = <*0*> ^ p holds
( t in Leaves (tree (T0,T1)) iff p in Leaves T0 ) ) & ( for p being Element of T1 st t = <*1*> ^ p holds
( t in Leaves (tree (T0,T1)) iff p in Leaves T1 ) ) )
set RT = tree (T0,T1);
hereby for p being Element of T1 st t = <*1*> ^ p holds
( t in Leaves (tree (T0,T1)) iff p in Leaves T1 )
let p be
Element of
T0;
( t = <*0*> ^ p implies ( ( t in Leaves (tree (T0,T1)) implies p in Leaves T0 ) & ( p in Leaves T0 implies t in Leaves (tree (T0,T1)) ) ) )assume A1:
t = <*0*> ^ p
;
( ( t in Leaves (tree (T0,T1)) implies p in Leaves T0 ) & ( p in Leaves T0 implies t in Leaves (tree (T0,T1)) ) )assume A4:
p in Leaves T0
;
t in Leaves (tree (T0,T1))assume
not
t in Leaves (tree (T0,T1))
;
contradictionthen consider n being
Nat such that A5:
t ^ <*n*> in tree (
T0,
T1)
by TREES_1:55;
<*0*> ^ (p ^ <*n*>) in tree (
T0,
T1)
by A1, A5, FINSEQ_1:32;
then
p ^ <*n*> in T0
by TREES_3:69;
hence
contradiction
by A4, TREES_1:55;
verum
end;
let p be Element of T1; ( t = <*1*> ^ p implies ( t in Leaves (tree (T0,T1)) iff p in Leaves T1 ) )
assume A6:
t = <*1*> ^ p
; ( t in Leaves (tree (T0,T1)) iff p in Leaves T1 )
assume A9:
p in Leaves T1
; t in Leaves (tree (T0,T1))
assume
not t in Leaves (tree (T0,T1))
; contradiction
then consider n being Nat such that
A10:
t ^ <*n*> in tree (T0,T1)
by TREES_1:55;
<*1*> ^ (p ^ <*n*>) in tree (T0,T1)
by A6, A10, FINSEQ_1:32;
then
p ^ <*n*> in T1
by TREES_3:70;
hence
contradiction
by A9, TREES_1:55; verum